anonymous
  • anonymous
In a right triangle named BAC, the hypotenus BA is 53 cm, AC is 28 and BC is 45. Find out HA, HO, OB, HC, CO.. |dw:1377791869950:dw|
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
||dw:1377791988664:dw|
anonymous
  • anonymous
|dw:1377792136232:dw|
anonymous
  • anonymous
are there any conditions for o and h

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anonymous
  • anonymous
CO is the mediane and CH the height.
anonymous
  • anonymous
then o is the mid point
anonymous
  • anonymous
Yes.
anonymous
  • anonymous
then it comes in points is it okay?
anonymous
  • anonymous
I have to find the other lenght with some formulas. Should I write them ?
anonymous
  • anonymous
*lenghts
anonymous
  • anonymous
what formula's
anonymous
  • anonymous
h^2=b'*c' b^2=b'*a or c^2=c'*a a^2=b^2+c^2 h=bc/a
anonymous
  • anonymous
if h=bc/a then bc=ah then ah=28
anonymous
  • anonymous
are abc the lenghts of the sides or the points write it with clarity
anonymous
  • anonymous
|dw:1377793043425:dw|
anonymous
  • anonymous
k now it is fine wait for a min i'l give you the answer
anonymous
  • anonymous
0b=26.5 as it is the mid point
anonymous
  • anonymous
28^2=oc^2+26.5^2 784=0c^2+702.25 0c^2=784-702.25 0c^2=81.75 0c=9.04
anonymous
  • anonymous
oh=0b/2 oh=26.5/2 oh=13.25
anonymous
  • anonymous
ha=oh+oa ha=39.75
anonymous
  • anonymous
a^2=b^2+c^2 This formula only works with a triangle with right angles.
anonymous
  • anonymous
ya CHB,CHO,COB,COA are right angle triangles
anonymous
  • anonymous
Not COB and COA.

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