anonymous
  • anonymous
What is the equation of the line, in slope-intercept form, that passes through the point (4, -1) and is perpendicular to the line whose equation is 2x - y - 7 = 0? y = -1/2x + 1 y = 1/2x - 1 y = 2x + 1
Algebra
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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OakTree
  • OakTree
Hi again. Like last time, we're going to want to start with the slope. So what's the slope of the line we're given?
OakTree
  • OakTree
@mjcobb2, do you know the slope of the line given?
anonymous
  • anonymous
No

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OakTree
  • OakTree
Okay then. So first we want to put it in slope-intercept form, which is y=2x-7. So the slope is 2. However, since the line we want is perpendicular, the slope of our line is the opposite reciprocal of 2, which is -1/2. So our slope is -1/2. For the next phase, we plug the slope and the point given into the slope-intercept formula, and we get \[-1 = \frac{ -1 }{ 2 } \times 4 + b\]Which yields b = -3. So our line is \[y = \frac{ -1 }{ 2 } x -3\]
OakTree
  • OakTree
Which, in the form you asked for last question, is the same as \[x + 2y + 6 = 0\]
anonymous
  • anonymous
Thank you very much I am taking a test and it is very hard as I really don't like these kind of questions...
OakTree
  • OakTree
No problem.

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