anonymous
  • anonymous
Sqrt -8x+6-3=8x... I need help solving !
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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OakTree
  • OakTree
Do you mean\[\sqrt{-8x+6} -3 = 8x\]
anonymous
  • anonymous
http://www.wolframalpha.com/input/?i=Sqrt+-8x%2B6-3%3D8x
anonymous
  • anonymous
Yes , I need all possible solutions .

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More answers

OakTree
  • OakTree
@Gabriel.Dalbani, stop just plugging things into WolframAlpha.
OakTree
  • OakTree
So what you need to do to solve, @Shgre17, is first move the -3 over to the right-hand side of the equation and then square both sides. So it should look like this:\[-8x + 6 = (8x + 3)^2\]
OakTree
  • OakTree
Following so far?
OakTree
  • OakTree
And thanks for the medal, @CGGURUMANJUNATH. I appreciate it.
anonymous
  • anonymous
Yes
CGGURUMANJUNATH
  • CGGURUMANJUNATH
you're welcome @OakTree
OakTree
  • OakTree
Great. So then we FOIL out the right hand side. Can you do that?
anonymous
  • anonymous
Yes I can, give me a sec to do the math @oaktree
CGGURUMANJUNATH
  • CGGURUMANJUNATH
wolfram alfa plugging directly gives wrong answer interpreting would be difficult.
anonymous
  • anonymous
After you foil you would end up with 16x^2+24x+24x+9 right?
OakTree
  • OakTree
Not quite. Your first term is wrong.
OakTree
  • OakTree
You see your mistake?
anonymous
  • anonymous
Lol sorry its 64x^2
OakTree
  • OakTree
Yeah. Now add the two middle terms and you get...?
anonymous
  • anonymous
48x
OakTree
  • OakTree
Right. So we have\[-8x + 6 = 64x^2 + 48x + 9\]Now combine like terms so we have a quadratic equation. We get\[64x^2 + 56x + 3 = 0\]Which doesn't factor nicely, so we have to use the quadratic formula. Do you know it?
anonymous
  • anonymous
It's ax^2+bx+c right ?
OakTree
  • OakTree
Not quite. The quadratic formula is \[x = \frac{ -b \pm \sqrt{b^2 - 4ac} }{ 2a }\]
anonymous
  • anonymous
Okay , so what do I do next?
OakTree
  • OakTree
Well, you take the values for a, b, and c from your equation and plug them in. The two answers you get (since it's plus and minus) are your roots. Okay?
OakTree
  • OakTree
So it would go like this:\[x = \frac{ -56 \pm \sqrt{56^2 - 4(64)(3)} }{ 2(3) }\]
anonymous
  • anonymous
Okay I have that
OakTree
  • OakTree
Which, simplified, is \[\frac{ -56 \pm 8 \sqrt{37} }{ 6 }\]
OakTree
  • OakTree
Now, do you think you can simplify that all the way and get your answers?
anonymous
  • anonymous
How did you get that ?
OakTree
  • OakTree
Simplify the inside of the square root.

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