anonymous
  • anonymous
Electrostatics: You have a hollow sphere with a charge -2Q it has an inner radius R1 and outer radius R2 there is nothing inside the hollow cavity. Find the charge density at R1 and R2.
Physics
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
My instructor told us this in lecture. I have written: "We can argue that the charge density on the inner surface at R1 is =0. The reasoning is that E lines must originate from + and terminate at - charges. If it is minus charged in the inner space there needs to be a positive charge to originate from but E=0 so that cannot happen"
anonymous
  • anonymous
|dw:1377798974315:dw|
anonymous
  • anonymous
Is what I have drawn. I do not understand what he meant at all. I don't know if he meant that the -2Q was on the inside or if that was just a hypothetical and the -2Q is still residing elsewhere.

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anonymous
  • anonymous
Charges will always lie only on the outer surface.. assuming its a conductor ofcourse.. and therefore.. what he is trying to say is that inside the conductor, charge must be zero and hence the charge density is also zero!
anonymous
  • anonymous
Could you explain that to me? I'm trying to reason through it. I'm stuck.
anonymous
  • anonymous
Is it because they would repel each other until they could get furthest away?
anonymous
  • anonymous
ys exactly.. charges in a conductor will always try to move away from each other as much as possible.. and in doing so they would always end up being on the surface .. :)
theEric
  • theEric
I would look into shell theory! If I remember correctly, that might be helpful!
anonymous
  • anonymous
Thanks! I'll look into shell theory too!

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