El_Tucan
  • El_Tucan
evaluating an integral:
Calculus1
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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El_Tucan
  • El_Tucan
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austinL
  • austinL
\[\int\limits_{0}^{7}\frac{1}{\sqrt{x+9}}dx\] u = x+9 du = dx \[=\int\limits_{0}^{7}\frac{1}{\sqrt{u}}du\] \[=2\sqrt{u} = 2\sqrt{x+9}\] Then Fundamental Theorem of Calculus.
anonymous
  • anonymous
\[\int\limits_{0}^{7}\frac{ dx }{\sqrt{x+9} }\] \[=\int\limits_{0}^{7}\left( x+9 \right)^{\frac{ -1 }{2 }}dx\] use the formula \[\int\limits f ^{n}\left( x \right)f \prime \left( x \right) dx=\frac{ f ^{n+1}\left( x \right) }{n+1 }\]

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El_Tucan
  • El_Tucan
thanks guys i got it...i get 2.
austinL
  • austinL
Woo, correct!!
anonymous
  • anonymous
just to note that u = x+9 so limits of integral in u where both perfect squares upper 16 and lower 9 easy to square root

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