anonymous
  • anonymous
Calculate the area of triangle RST
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
https://byuis.brainhoney.com/Resource/10035010,817,0/Assets/Media/Images/GEOM043_CSR2-6.jpg
anonymous
  • anonymous
a.121 b.30.25 c.60.5 d.104.8
jdoe0001
  • jdoe0001
notice in your triangle you have a 30 degree angle up above you also have a 90 degree angle at the bottom left what degree do you think is the other angle to the bottom right?

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More answers

anonymous
  • anonymous
60 on the right
anonymous
  • anonymous
i tried using the 30 60 90 but i didn't get the answer
jdoe0001
  • jdoe0001
hmm, what did you get for the SR side?
jdoe0001
  • jdoe0001
using 30-60-90 rule that is
anonymous
  • anonymous
Short Leg(2)= Hyp and Short Leg(sqrt3)=Long Leg
jdoe0001
  • jdoe0001
right
jdoe0001
  • jdoe0001
and you have the "shortest leg", so you can get the other leg right?
jdoe0001
  • jdoe0001
keep in mind that ST = shortest leg = BASE SR = longer leg = altitude = height Area of a triangle = \(\bf \cfrac{1}{2}\times base \times height\)
anonymous
  • anonymous
i got 121 sqrt 3
jdoe0001
  • jdoe0001
hmmm |dw:1377808513502:dw| \(\bf Area =\cfrac{1}{2}\times base \times height \implies \cfrac{1}{2}\times 11 \times 11\sqrt{3} \implies \cfrac{121\sqrt{3}}{2}\)
anonymous
  • anonymous
60.5?
jdoe0001
  • jdoe0001
well, if you want a decimal figure, yes 121/2 = 60.5, you still have a \(\bf \sqrt{3}\) too btw
anonymous
  • anonymous
:( i am lost...
jdoe0001
  • jdoe0001
hmm, are you using Internet Explorer? if you don't mind me asking
anonymous
  • anonymous
chrome
jdoe0001
  • jdoe0001
ok... so . what ... part did you find confusing?
jdoe0001
  • jdoe0001
\(\bf \cfrac{1}{2}\times \color{red}{base} \times \color{blue}{height} \implies \cfrac{1}{2}\times \color{red}{11} \times \color{blue}{11\sqrt{3}} \implies \cfrac{121\sqrt{3}}{2}\)
anonymous
  • anonymous
like we ended up with 2 answers 60.5 and 121 but we also need the sqrt 3 i don't know what's the answer
jdoe0001
  • jdoe0001
well, the answer would be \(\bf \cfrac{121\sqrt{3}}{2}\)
anonymous
  • anonymous
so it's 121?
jdoe0001
  • jdoe0001
because that's what you'd get from \(\bf \cfrac{1}{2}\times base \times height\)
jdoe0001
  • jdoe0001
well, you can leave it as a fraction, or you can use \(\bf \cfrac{121\sqrt{3}}{2}\implies \cfrac{121}{2} \times \sqrt{3}\implies 60.5 \times \sqrt{3}\implies 60.5 \times 1.7320 \approx 10.4789\)
jdoe0001
  • jdoe0001
hmm have a typo there one sec
jdoe0001
  • jdoe0001
\(\bf \cfrac{121\sqrt{3}}{2}\implies \cfrac{121}{2} \times \sqrt{3}\implies 60.5 \times \sqrt{3}\implies 60.5 \times 1.7320 \approx 104.789\)
anonymous
  • anonymous
okay then the final would be 104.8 (rounded)
jdoe0001
  • jdoe0001
yes
anonymous
  • anonymous
okay thank you!! and i need some help on these other problems. can you help me please?
jdoe0001
  • jdoe0001
sure, just post anew so we can all see it and help and revise each other
anonymous
  • anonymous
okay!

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