• anonymous
Mark is in a deep hole looking for treasure. He is standing 8 feet below the surface. He throws an old watch he found with an initial upward velocity of 23 ft/sec. How long until it lands outside the hole, having gone up and back down? Use the formula (h=-16t^2+23t-8) where h is the height of the watch in feet (relative to the surface) and t is the time in seconds since Mark threw it. Ignore air resistance and round your answer to the nearest tenth. A. 0.3 seconds B. 0.8 seconds C. 2.1 seconds D. It will not make it outside the hole.
  • Stacey Warren - Expert
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  • katieb
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  • anonymous
please help me

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