anonymous
  • anonymous
State the horizontal asymptote of the rational function. f(x) = x^2 + 8x - 2 / x - 2
Mathematics
  • Stacey Warren - Expert brainly.com
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katieb
  • katieb
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jdoe0001
  • jdoe0001
\(\bf f(x) = \cfrac{x^2 + 8x - 2 }{ x - 2} \quad ?\)
jdoe0001
  • jdoe0001
if that's the case, you really only get a horizontal asymptote when the denominator's "degree" is higher OR equal to the numerator's
anonymous
  • anonymous
^ yes and these are the answer choices: None y = 1 y = -8 y = 2 @jdoe0001

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jdoe0001
  • jdoe0001
ok, then you'd know the answer by now then :) what's the degree of the polynomial at the numerator? what about the degree of the one in the denominator?
anonymous
  • anonymous
2 and then 1
jdoe0001
  • jdoe0001
yes, so there
anonymous
  • anonymous
But those are both different answer choices
jdoe0001
  • jdoe0001
----> if that's the case, you really only get a horizontal asymptote when the denominator's "degree" is higher OR equal to the numerator's <----
anonymous
  • anonymous
so 1 !
jdoe0001
  • jdoe0001
1? y = 1?
anonymous
  • anonymous
2?
jdoe0001
  • jdoe0001
hmmmm do you know what -> you really only get a horizontal asymptote when the denominator's "degree" is higher OR equal to the numerator's <- mean?
jdoe0001
  • jdoe0001
if the polynomial in the denominator has a higher degree than that of the numerator's, then you have a horizontal asymptote, otherwise, you don't
anonymous
  • anonymous
Okay so it's none ?
jdoe0001
  • jdoe0001
higher or equal btw if the numerator's "degree" is higher than the denominator's, then you have no horizontal asymptotes
jdoe0001
  • jdoe0001
so, yes, in this case the degree of the numerator is 2, the denominator is 1 so the numerator's degree is higher, thus no horizontal asymptotes
anonymous
  • anonymous
Thank youu ((:
jdoe0001
  • jdoe0001
yw

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