ExplainItLikeImFive
  • ExplainItLikeImFive
Write the equation in terms of a rotated x'y'-system using θ, the angle of rotation. Write the equation involving x' and y' in standard form.
Precalculus
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
jamiebookeater
  • jamiebookeater
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
ExplainItLikeImFive
  • ExplainItLikeImFive
1 Attachment
zepdrix
  • zepdrix
Hmm I dont' really remember how to rotate axes. My book is giving me these formulas though:\[\Large x=x' \cos \theta-y' \sin \theta\]\[\Large y=x' \sin \theta+y' \cos \theta\]
zepdrix
  • zepdrix
Where theta is the angle of rotation. So if we plug them in,\[\large xy=-16 \quad\to\quad \left(x'\frac{1}{\sqrt2}-y'\frac{1}{\sqrt2}\right)\left(x'\frac{1}{\sqrt2}+y'\frac{1}{\sqrt2}\right)=-16\]

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

zepdrix
  • zepdrix
From there it just requires a bit of simplification :o
ExplainItLikeImFive
  • ExplainItLikeImFive
That is where I am stuck :/
zepdrix
  • zepdrix
Let's factor the fraction out of each set of brackets.\[\Large \frac{1}{\sqrt2}\cdot\left(x'-y'\right)\frac{1}{\sqrt2}\cdot\left(x'+y'\right)=-16\]
zepdrix
  • zepdrix
So we have:\[\Large (x'-y')(x'+y')=-32\]
ExplainItLikeImFive
  • ExplainItLikeImFive
That was really helpful. Thank you very much. I've been trying to get help with this for 3 days.
zepdrix
  • zepdrix
ah that sucks :c

Looking for something else?

Not the answer you are looking for? Search for more explanations.