tracyy
  • tracyy
Simple question: How would I complete the square for this?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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tracyy
  • tracyy
x^2 − 10x + y^2 − 6y − 30 = 0
tracyy
  • tracyy
What I have so far is: (x^2 - 10x ____) + (y^2-6y ____) - 30 = 0
Luigi0210
  • Luigi0210
To find C: \[(\frac{b}{2})^2\] Right?

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tracyy
  • tracyy
I'm supposed to complete the square on x and y terms to find the center and radius of a circle, which I know how to do. I am just stuck at completing the square for this equation.
Luigi0210
  • Luigi0210
Well move the 30 over and divide b by 2 then square it
DebbieG
  • DebbieG
For the x portion of the equation, b=-10. Do like @Luigi0210 says, take half of that and square it, add it inside the ( ) AND ALSO ON THE OTHER SIDE. For the y portion of the equation, b=-6. Again, take half of that and square it, add it inside the ( ) AND ALSO ON THE OTHER SIDE. Also move the -30 to the other side. when you do all that (and simplify the RHS, and factor the perfect squares on the LHS) you will have your circle equation.

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