anonymous
  • anonymous
REWARD AND MEDAL 2.) Grace leaves home at 8am TEN minutes later, Will notices Grace's lunch and begins bicycling after her. If Grace walks at 5km/h and Will cycles at 15 km/h, how long will it take him to catch up with her??????
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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jdoe0001
  • jdoe0001
hmm, I see, she left at 8am, and forgot her lunch anyhow so how long do you think Will would have traveled in distance when he catches up with her? would you say by that time they'd have traveled the same distance?
jim_thompson5910
  • jim_thompson5910
10 minutes = 10/60 = 1/6 hours let t = time elapsed (in hours) from when Grace leaves home If Grace walks at 5 km/hr, then she will walk a total of 5t kilometers when she walks for t hours. Will starts ten minutes or 1/6 hour later, so he will bike for t - 1/6 hours. This means he travels 15(t -1/6) km
anonymous
  • anonymous
idk

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jdoe0001
  • jdoe0001
say, you leave home at 8am, and then your brother catches up with you by the time your brother, also from home, catches up with you, you have already walked 2 miles how long has he walked too?
anonymous
  • anonymous
2 miles?
jdoe0001
  • jdoe0001
if you had walked 2 miles, and your brother walked 3 miles so he really passed you by, by 1 mile if you had walked 2 miles, and your brother walked 1 mile so he's still 1 mile behind you if you had walked 2 miles, and your brother walked 1 1/2 miles he hasn't gotten to you, he's still behind
jdoe0001
  • jdoe0001
however if you walked 2 miles, and he walked 2 miles, both from home has he caught up with you? or pass you by or still behind you?
anonymous
  • anonymous
you aren't making sense.. can u just tell me what goes in the chart then tell me the equation??
jdoe0001
  • jdoe0001
lol
jdoe0001
  • jdoe0001
well, that's the idea behind it
anonymous
  • anonymous
can u tell me itd be helping me
jdoe0001
  • jdoe0001
anyhow, jim_thompson5910 already typed it in
jim_thompson5910
  • jim_thompson5910
grace walks 5t km will bikes 5(t-1/6) km the two will meet when the two distances are the same, so you need to solve 5t = 5(t-1/6)
jim_thompson5910
  • jim_thompson5910
sorry typo
jim_thompson5910
  • jim_thompson5910
will bikes 15(t-1/6), so the equation should be 5t = 15(t - 1/6)
anonymous
  • anonymous
how do u solve with the 1/6??
jim_thompson5910
  • jim_thompson5910
5t = 15(t - 1/6) 5t = 15t - 15(1/6) ... distribute 5t = 15t - 15/6 ... multiply 5t = 15t - 5/2 ... reduce I'll let you finish up
anonymous
  • anonymous
subtract 5t next?
jim_thompson5910
  • jim_thompson5910
15t actually
anonymous
  • anonymous
5t=-5/2
anonymous
  • anonymous
???? is that right
anonymous
  • anonymous
T=-1/2 answer so -1/2 hours
jim_thompson5910
  • jim_thompson5910
5t - 15t = ???
anonymous
  • anonymous
i didn't put that anywhere
jim_thompson5910
  • jim_thompson5910
what is 5t - 15t
anonymous
  • anonymous
ys
jim_thompson5910
  • jim_thompson5910
simplify 5t - 15t for me
anonymous
  • anonymous
-10t
jim_thompson5910
  • jim_thompson5910
so we now have -10t = -5/2 t = ??
anonymous
  • anonymous
x=-1/4
jim_thompson5910
  • jim_thompson5910
it's positive though
jim_thompson5910
  • jim_thompson5910
t = 1/4
jim_thompson5910
  • jim_thompson5910
so it takes 1/4 of an hour or 15 minutes for Will to catch up to Grace
anonymous
  • anonymous
how long would that be??
anonymous
  • anonymous
oh ok 15 or 1/4 of an hour. THANKS SO MUCH im posting another question sticka round
anonymous
  • anonymous
3.) a jet took one hour longer flying to Lincoln from Adams at 800 km/h than to return at 1200 km/h find the distance from Lincoln to Adams????
anonymous
  • anonymous
@jim_thompson5910

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