anonymous
  • anonymous
Troubles with Polynomials (writing equation incoming)
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
\[\frac{ t }{ t+3 }+\frac{ 4t }{ t-3 }-\frac{ 18 }{ t ^{2}-9}\]
anonymous
  • anonymous
I have started on the bottom with \[\frac{ t \left( t-3 \right) }{\left( t+3 \right)\left( t-3 \right) }+\frac{ 4t \left( t+3 \right) }{ t-3\left( t+3 \right) }-\frac{ 18 }{ t ^{2}-9 }\]
anonymous
  • anonymous
Okay so whats the problem?

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More answers

anonymous
  • anonymous
I guess when I work it out I am etting the wrong answer
anonymous
  • anonymous
I get that but are you trying to find t?
anonymous
  • anonymous
\[\frac{ t ^{2}-3+4t ^{2}+3-18 }{ t ^{2-9} }\]
anonymous
  • anonymous
no simplify
anonymous
  • anonymous
looks simplified to me.
anonymous
  • anonymous
just add t^2 and t^2
anonymous
  • anonymous
I do and still get the wrong answer when applying it to my homework, I can't seem to find my mistake
anonymous
  • anonymous
well add up all the number on the top.
anonymous
  • anonymous
I do I know the answer should be \[\frac{ 5t-6 }{ t-3 }\] when you add up the above you get \[\frac{ 5t^2-18 }{ t^2-9 }\]
anonymous
  • anonymous
looks good.
anonymous
  • anonymous
No becuase I am not getting the right answer
anonymous
  • anonymous
The top I just posted I know is the answer, but I cant find out how to get there from where I am
anonymous
  • anonymous
You distributed incorrectly. The term being multiplied by the parenthesis has to multiply by both terms inside.
anonymous
  • anonymous
?
anonymous
  • anonymous
\[t(t-3) = t^2-3t\]
anonymous
  • anonymous
Same problem with the middle term.
anonymous
  • anonymous
Ok so that makes is what t^2+9t-18 on top?
anonymous
  • anonymous
Not quite. Show me your distribution on the second term.
anonymous
  • anonymous
When I multiple them across like I have them on top I get this \[t ^{2}-3t+4t ^{2}+12t-18\]
anonymous
  • anonymous
Exactly. What is 4+1?
anonymous
  • anonymous
5t^2 >.<
anonymous
  • anonymous
Great. Please continue... :-)
anonymous
  • anonymous
You are only supposed to simplify, correct?
anonymous
  • anonymous
So the problem is now \[\frac{( t+3)(5t-6) }{ (t+3)(t-3) }\] the (t+3) cancel out making the problem \[\frac{ 5t-6 }{ t-3 }\]
anonymous
  • anonymous
Yes, that is the answer I got.
anonymous
  • anonymous
ty for finding my rewrite mistakes
anonymous
  • anonymous
Glad to help. I've made many of those mistakes myself.

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