Please show me how to solve this and check for extraneous solutions. 3x^4/3-7=41

Please show me how to solve this and check for extraneous solutions. 3x^4/3-7=41

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Do you mean\[\frac{ 3x^4 }{ 3 } - 7 = 41\]Or is (3-7) in the denominator?

No, 3 is the denominator for the 4 only. Its part of that exponent

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