anonymous
  • anonymous
Please show me how to solve this and check for extraneous solutions. 3x^4/3-7=41
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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OakTree
  • OakTree
Do you mean\[\frac{ 3x^4 }{ 3 } - 7 = 41\]Or is (3-7) in the denominator?
anonymous
  • anonymous
No, 3 is the denominator for the 4 only. Its part of that exponent
OakTree
  • OakTree
Okay. So can you start off by isolating the 3x^4? Can you do that by yourself, or do you need help with that?

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anonymous
  • anonymous
I need help because I don't know how to do 3x^4/3
OakTree
  • OakTree
Wait...is it \[3x^{4/3}\]or what I wrote up there?
anonymous
  • anonymous
Yes. Its the new one u just wrote
OakTree
  • OakTree
Okay. Now I understand why you're having problems. What you need to first do is isolate the x, so we have\[x^{4/3} = 16\]Now we need to figure out what to do with the exponent. What you need to do is raise both sides to the 3/4 power. This will give us just an x on the left side.\[(x^{4/3})^{3/4} = x = 16^{3/4} = \sqrt[4]{16^3} = 2^3 = 8\]So x=8. Do you need me to go over the last part?
OakTree
  • OakTree
@Dee1516?
OakTree
  • OakTree
And thanks for the medal, @DebbieG. I appreciate it.
DebbieG
  • DebbieG
No problem :)
anonymous
  • anonymous
Thank you so much! @oaktree
OakTree
  • OakTree
No problem. I'm glad I could help. :)
anonymous
  • anonymous
Can you help me with this one as well 4(x-3)^3/2+12=120
anonymous
  • anonymous
@oaktree
OakTree
  • OakTree
Already here! Same idea. Subtract 12 and divide by 4 to get\[(x-3)^{3/2} = 27\]Then raise both sides to the 2/3 power and you get\[x-3 = 27^{2/3} = ((27)^{1/3})^2 = 3^2 = 9\]But don't forget we still need to isolate the x! So we add 3 and get x=12.
OakTree
  • OakTree
Good?
anonymous
  • anonymous
Yes! Thank you so much!!!!
OakTree
  • OakTree
Great. Just fan me or write a testimonial or something and that way you can send me a call next time you have a problem. Glad to help!
anonymous
  • anonymous
Okay!

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