• anonymous
draw two structures one straight chain and one ring of a carbohydrate with the chemical formula of (ch2o)6
  • Stacey Warren - Expert
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  • schrodinger
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  • e.cociuba
For the chain: ...OH..H..OH..OH ......I.....I....I....I R---C---C---C---C---CH2OH ......I.....I....I....I .....H..OH..H...H Substitute the R with CHO (this is an aldehyde with a terminal carbonyl-group and an attached hydrogen) carbonyl-group: C=O The structure of the aldehyde is not linear! note: remember that the C in the aldehyde stands right (connected with the last C) when you draw it. For the ring form you should read about monosacharides and their cyclic forms. Since you have 6 carbon atoms I guess the ring will be a pyranose ring (6 edges) with a ring oxygen (oxygen bridge). This can easily be looked up with a bit of research put into it.
  • goformit100
First of all @tyler24732 : A Warm Welcome to 'Open Study'. Please Read CoC (compulsory to read by all "Open Study" users) :

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