anonymous
  • anonymous
5)At noon, Sheila left a boat landing and paddled her canoe 20 km downstream and 20 km back. if she traveled 10km/h downstream and 4 km/h upstream, what time did she arrive back at the landing????
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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Mertsj
  • Mertsj
Do you know that rate multiplied by time = distance?
anonymous
  • anonymous
yesss
Mertsj
  • Mertsj
Then find how long it took to go 20 km downstream.

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More answers

anonymous
  • anonymous
idk how? honest
Mertsj
  • Mertsj
How far downstream did she go?
anonymous
  • anonymous
20km
Mertsj
  • Mertsj
|dw:1377828382982:dw|
Mertsj
  • Mertsj
That is distance. Replace distance with 20
Mertsj
  • Mertsj
How fast was she traveling downstream?
anonymous
  • anonymous
10km/h
Mertsj
  • Mertsj
That is the rate. Replace rate with 10. Find the time.
anonymous
  • anonymous
10x=20 ?
Mertsj
  • Mertsj
|dw:1377828552953:dw|
anonymous
  • anonymous
10 is answer?
Mertsj
  • Mertsj
So do you really think that 10 times 10 = 20 or are you just being a smart aleck?
anonymous
  • anonymous
noo )': I said 10t=20 10t/10=20/10 t=10 10=answer? im not being cocky )'; )';
Mertsj
  • Mertsj
Do you really think that 20 divided by 10 is 10?
anonymous
  • anonymous
ohh 2. my bad.. a yeah I did.. jeezz
Mertsj
  • Mertsj
2 what?
anonymous
  • anonymous
please help w/5 more? 2pm
Mertsj
  • Mertsj
2 hours. It took her 2 hours to go 20 km downstream because she was traveling 10 km each hour so it took her 2 hours to go 20 km.
Mertsj
  • Mertsj
She left at noon. So now she is 20 km downstream and it it 2 pm.
anonymous
  • anonymous
it says what time did she arrive back at the landing, what time
Mertsj
  • Mertsj
Now she has to go back. So she has to travel 20 km again. How fast is she going this time?
anonymous
  • anonymous
20(2)?
Mertsj
  • Mertsj
Read the problem. How fast is she going on the return trip?
anonymous
  • anonymous
20(4)?
Mertsj
  • Mertsj
So you are saying she is traveling 80 km per hour on the return trip?
anonymous
  • anonymous
20/4?
Mertsj
  • Mertsj
Why can't you do the same thing you did before and replace distance with 20 and rate with 4 and solve for time?
anonymous
  • anonymous
5
anonymous
  • anonymous
I got 5 doing it how u just said
Mertsj
  • Mertsj
5 what?
anonymous
  • anonymous
2pm,5pm
anonymous
  • anonymous
???????? is it 2pm, 5pm? @Mertsj
Mertsj
  • Mertsj
I thought you were solving for time?
Mertsj
  • Mertsj
If you leave at noon and you travel for 2 hours and then you turn around and travel for 5 more hours, what time is it now?
anonymous
  • anonymous
7 pm
anonymous
  • anonymous
?
Mertsj
  • Mertsj
yep
anonymous
  • anonymous
so 5pm, 7pm?
anonymous
  • anonymous
my bad I meant. 2pm, 7pm?????
Mertsj
  • Mertsj
How long did it take her to get 20 km downstream?
anonymous
  • anonymous
5pm,7pm???
Mertsj
  • Mertsj
rt=d 10t=20 t=2 hours She left at noon. She traveled 2 hours to get 20 km downstream. It is now 2 pm She turned around at 2 pm rt=d 4t=20 t=5 hours She turned around at 2 pm. She traveled for 5 hours to get back. It is now 7 pm
anonymous
  • anonymous
I don't understand if theres suppose to be 1 or 2 answers?
Mertsj
  • Mertsj
What does the problem ask?
anonymous
  • anonymous
1 answer I think
anonymous
  • anonymous
soooo 7pm is the answer
Mertsj
  • Mertsj
I have noticed that you have a real problem answering the question you are asked. Reread this discussion and notice how many questions I asked you that you answered with something other than the answer to that specific question. That same problem caused you to be unable to answer the question the problem asked even after you had it solved. If you focus on answering the EXACT question you are asked, it will be a help to you.
anonymous
  • anonymous
thanks, sorry. my bad...
anonymous
  • anonymous
thanks for the help with that problem
Mertsj
  • Mertsj
yw
anonymous
  • anonymous
will u pleaseee help me w/more? on here on this chat discussion
Mertsj
  • Mertsj
Post it. I have a little more time.
anonymous
  • anonymous
9.) At 10:30 a.m. two planes leave Houston, one flying east at 560 km/h and the other flying west at 640 km/h. at what time will they be 2100 km apart?
Mertsj
  • Mertsj
The distance of the first plane is 560t The distance of the second plane is 640t The sum of the two distances must be 2100 Write and solve that equation.
anonymous
  • anonymous
560+640=2100
Mertsj
  • Mertsj
What is the distance of the first plane?
Mertsj
  • Mertsj
The distance of the first plane is 560t
Mertsj
  • Mertsj
What is the distance of the first plane?
anonymous
  • anonymous
560t +640t=2100 1100t=2100 1100t/1100=2100/1100 x=
anonymous
  • anonymous
is it set up like that?
Mertsj
  • Mertsj
Yes. But 560 +640 is not 1100
anonymous
  • anonymous
1200
anonymous
  • anonymous
I got T=1 pm for answer... is that right??????
anonymous
  • anonymous
@Mertsj
Mertsj
  • Mertsj
What did you get for t ?

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