anonymous
  • anonymous
Find the equation of the circle which passes through the points (2, 3) and (-1, 1) and has its center on the line x – 3y – 11 = 0.
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
lord i bet this is going to be a pain lets solve for \(x\)
anonymous
  • anonymous
get \(x=3y+11\) so any point on the line will look like \((3y+11,y)\)
anonymous
  • anonymous
the square of the distance between \((3y+11,y)\) and \((2,3)\) must equal the square of the distance between \((3y+11,y)\) and \((-1,1)\)

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anonymous
  • anonymous
in other words \[(3y+11-2)^2+(y-3)^2=(3y+11+1)^2+(y-1)^2\] simplify this mess and solve for \(y\) then solve for \(x\) and you will have the center
anonymous
  • anonymous
if it was me, i would cheat
anonymous
  • anonymous
@Loser66 look good to you?
Loser66
  • Loser66
XD yup.

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