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Allypally Group Title

How do I graph y=x2+6x+5

  • one year ago
  • one year ago

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  1. OpenSessame Group Title
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    Do you have a TI-83?

    • one year ago
  2. Allypally Group Title
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    No

    • one year ago
  3. OpenSessame Group Title
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    Ohkay...

    • one year ago
  4. OpenSessame Group Title
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    http://www.algebra.com/algebra/homework/Rational-functions/Rational-functions.faq.question.430102.html

    • one year ago
  5. OpenSessame Group Title
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    look at the graph and then ill explain how you can draw the parabola.

    • one year ago
  6. Allypally Group Title
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    Ok that equation isn't the same as mine

    • one year ago
  7. OpenSessame Group Title
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    I know, but i just wanted you to see sort of what it would look like...

    • one year ago
  8. Allypally Group Title
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    Oh ok I know how to solve it, but when I graph it it doesn't curve

    • one year ago
  9. OpenSessame Group Title
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    What do you mean?

    • one year ago
  10. OpenSessame Group Title
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    Did you do the three point thing?

    • one year ago
  11. Allypally Group Title
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    No

    • one year ago
  12. OpenSessame Group Title
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    You should do that...Find the Lowest point.

    • one year ago
  13. OpenSessame Group Title
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    You can either make a table or factor it to get started.

    • one year ago
  14. OpenSessame Group Title
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    |dw:1377833307947:dw|

    • one year ago
  15. OpenSessame Group Title
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    Continue the table!

    • one year ago
  16. Allypally Group Title
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    |dw:1377833554345:dw|

    • one year ago
  17. Allypally Group Title
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    the thing is no matter how much I ad the graph never curves

    • one year ago
  18. Allypally Group Title
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    add**

    • one year ago
  19. Luigi0210 Group Title
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    Welcome to openstudy :) Do you need any more help?

    • one year ago
  20. OpenSessame Group Title
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    Hmm...Let me graph it on my calc and see whats up!

    • one year ago
  21. OpenSessame Group Title
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    IT CURVES!

    • one year ago
  22. wolf1728 Group Title
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    You can get a rough idea of the graph from 2 things: 1) The coefficient of x² If it is positive, the graph will be concave up. (shaped like a 'U'). 2) Solve for x. The roots of the equation are -1 and -5 These are the two points where the parabola crosses the x axis. With this small amount of information, we can make a rough graph of the equation.

    • one year ago
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