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Allypally
 2 years ago
How do I graph y=x2+6x+5
Allypally
 2 years ago
How do I graph y=x2+6x+5

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OpenSessame
 2 years ago
Best ResponseYou've already chosen the best response.0Do you have a TI83?

OpenSessame
 2 years ago
Best ResponseYou've already chosen the best response.0look at the graph and then ill explain how you can draw the parabola.

Allypally
 2 years ago
Best ResponseYou've already chosen the best response.0Ok that equation isn't the same as mine

OpenSessame
 2 years ago
Best ResponseYou've already chosen the best response.0I know, but i just wanted you to see sort of what it would look like...

Allypally
 2 years ago
Best ResponseYou've already chosen the best response.0Oh ok I know how to solve it, but when I graph it it doesn't curve

OpenSessame
 2 years ago
Best ResponseYou've already chosen the best response.0Did you do the three point thing?

OpenSessame
 2 years ago
Best ResponseYou've already chosen the best response.0You should do that...Find the Lowest point.

OpenSessame
 2 years ago
Best ResponseYou've already chosen the best response.0You can either make a table or factor it to get started.

OpenSessame
 2 years ago
Best ResponseYou've already chosen the best response.0dw:1377833307947:dw

OpenSessame
 2 years ago
Best ResponseYou've already chosen the best response.0Continue the table!

Allypally
 2 years ago
Best ResponseYou've already chosen the best response.0dw:1377833554345:dw

Allypally
 2 years ago
Best ResponseYou've already chosen the best response.0the thing is no matter how much I ad the graph never curves

Luigi0210
 2 years ago
Best ResponseYou've already chosen the best response.0Welcome to openstudy :) Do you need any more help?

OpenSessame
 2 years ago
Best ResponseYou've already chosen the best response.0Hmm...Let me graph it on my calc and see whats up!

wolf1728
 2 years ago
Best ResponseYou've already chosen the best response.0You can get a rough idea of the graph from 2 things: 1) The coefficient of x² If it is positive, the graph will be concave up. (shaped like a 'U'). 2) Solve for x. The roots of the equation are 1 and 5 These are the two points where the parabola crosses the x axis. With this small amount of information, we can make a rough graph of the equation.
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