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OpenSessameBest ResponseYou've already chosen the best response.0
Do you have a TI83?
 7 months ago

OpenSessameBest ResponseYou've already chosen the best response.0
look at the graph and then ill explain how you can draw the parabola.
 7 months ago

AllypallyBest ResponseYou've already chosen the best response.0
Ok that equation isn't the same as mine
 7 months ago

OpenSessameBest ResponseYou've already chosen the best response.0
I know, but i just wanted you to see sort of what it would look like...
 7 months ago

AllypallyBest ResponseYou've already chosen the best response.0
Oh ok I know how to solve it, but when I graph it it doesn't curve
 7 months ago

OpenSessameBest ResponseYou've already chosen the best response.0
Did you do the three point thing?
 7 months ago

OpenSessameBest ResponseYou've already chosen the best response.0
You should do that...Find the Lowest point.
 7 months ago

OpenSessameBest ResponseYou've already chosen the best response.0
You can either make a table or factor it to get started.
 7 months ago

OpenSessameBest ResponseYou've already chosen the best response.0
dw:1377833307947:dw
 7 months ago

OpenSessameBest ResponseYou've already chosen the best response.0
Continue the table!
 7 months ago

AllypallyBest ResponseYou've already chosen the best response.0
dw:1377833554345:dw
 7 months ago

AllypallyBest ResponseYou've already chosen the best response.0
the thing is no matter how much I ad the graph never curves
 7 months ago

Luigi0210Best ResponseYou've already chosen the best response.0
Welcome to openstudy :) Do you need any more help?
 7 months ago

OpenSessameBest ResponseYou've already chosen the best response.0
Hmm...Let me graph it on my calc and see whats up!
 7 months ago

wolf1728Best ResponseYou've already chosen the best response.0
You can get a rough idea of the graph from 2 things: 1) The coefficient of x² If it is positive, the graph will be concave up. (shaped like a 'U'). 2) Solve for x. The roots of the equation are 1 and 5 These are the two points where the parabola crosses the x axis. With this small amount of information, we can make a rough graph of the equation.
 7 months ago
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