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OpenSessame
 one year ago
Best ResponseYou've already chosen the best response.0Do you have a TI83?

OpenSessame
 one year ago
Best ResponseYou've already chosen the best response.0look at the graph and then ill explain how you can draw the parabola.

Allypally
 one year ago
Best ResponseYou've already chosen the best response.0Ok that equation isn't the same as mine

OpenSessame
 one year ago
Best ResponseYou've already chosen the best response.0I know, but i just wanted you to see sort of what it would look like...

Allypally
 one year ago
Best ResponseYou've already chosen the best response.0Oh ok I know how to solve it, but when I graph it it doesn't curve

OpenSessame
 one year ago
Best ResponseYou've already chosen the best response.0Did you do the three point thing?

OpenSessame
 one year ago
Best ResponseYou've already chosen the best response.0You should do that...Find the Lowest point.

OpenSessame
 one year ago
Best ResponseYou've already chosen the best response.0You can either make a table or factor it to get started.

OpenSessame
 one year ago
Best ResponseYou've already chosen the best response.0dw:1377833307947:dw

OpenSessame
 one year ago
Best ResponseYou've already chosen the best response.0Continue the table!

Allypally
 one year ago
Best ResponseYou've already chosen the best response.0dw:1377833554345:dw

Allypally
 one year ago
Best ResponseYou've already chosen the best response.0the thing is no matter how much I ad the graph never curves

Luigi0210
 one year ago
Best ResponseYou've already chosen the best response.0Welcome to openstudy :) Do you need any more help?

OpenSessame
 one year ago
Best ResponseYou've already chosen the best response.0Hmm...Let me graph it on my calc and see whats up!

wolf1728
 one year ago
Best ResponseYou've already chosen the best response.0You can get a rough idea of the graph from 2 things: 1) The coefficient of x² If it is positive, the graph will be concave up. (shaped like a 'U'). 2) Solve for x. The roots of the equation are 1 and 5 These are the two points where the parabola crosses the x axis. With this small amount of information, we can make a rough graph of the equation.
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