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madsmckell

word problem!! A parcel of land is 6ft longer than it is wide. Each diagonal from one corner to the opposite corner is 174 ft long. What are the dimensions of the parcel?

  • 7 months ago
  • 7 months ago

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  1. gypsy1274
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    Draw a picture. That will help you figure out what to do.

    • 7 months ago
  2. OpenSessame
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    |dw:1377832287651:dw|

    • 7 months ago
  3. madsmckell
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    thanks but how do I solve it?

    • 7 months ago
  4. gypsy1274
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    It is 6 feet longer than it is wide, so you can write an expression for both the length and the width.

    • 7 months ago
  5. madsmckell
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    okay.... i did that... then what?:)

    • 7 months ago
  6. gypsy1274
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    Use the Pythagorean theorem.

    • 7 months ago
  7. gypsy1274
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    |dw:1377832617688:dw|

    • 7 months ago
  8. madsmckell
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    so... (w+6)^2+w^2=174^2??????

    • 7 months ago
  9. gypsy1274
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    Exactly.

    • 7 months ago
  10. gypsy1274
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    Solve for w.

    • 7 months ago
  11. madsmckell
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    okay i will tryyyy

    • 7 months ago
  12. gypsy1274
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    You can do it! I have faith in you!!

    • 7 months ago
  13. madsmckell
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    i was trying to solve for w but i got stuck... will someone help me and walk me through it??

    • 7 months ago
  14. gypsy1274
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    Stuck where? Show your steps and I will help you?

    • 7 months ago
  15. madsmckell
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    (w+6)^2+w^2=30276..... w^2+12w+36+w^2=30276......2w^2+12w+36=30267

    • 7 months ago
  16. madsmckell
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    and now im stuck

    • 7 months ago
  17. madsmckell
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    i was trying to use the quadratic formula but i wasnt sure what to do and my numbers were wayyyyyy big

    • 7 months ago
  18. gypsy1274
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    Great job! Find a calculator, you are going to need it. :-) The quadratic formula is what you will need. I'm still working through it. Before you get to that, get all terms to the left side of the equation and set it equal to 0.

    • 7 months ago
  19. gypsy1274
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    The numbers do get big, but you can handle it, with your calculator's help.

    • 7 months ago
  20. madsmckell
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    when i do the quadratic inside the root is negative so how would i simplify it??? isnt the quadratic formula -b plus or minus the root of b^2-4ac all over 2a

    • 7 months ago
  21. gypsy1274
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    It is not negative. You dropped a negative on the floor....look around, I'm sure it is still nearby. :-)

    • 7 months ago
  22. gypsy1274
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    One you get all the terms to the left side, the constant term will be negative.

    • 7 months ago
  23. gypsy1274
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    I divided the whole equation by 2 to keep the numbers smaller. \(w^2+6w-15120\)

    • 7 months ago
  24. madsmckell
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    but when you put in -15120 it is negative in the root soo it wont workkk

    • 7 months ago
  25. madsmckell
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    the answer in the back of the book is 120 by 126

    • 7 months ago
  26. madsmckell
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    so still not sure how that works when what ever i root comes out to be a decimal

    • 7 months ago
  27. gypsy1274
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    The answer in the back of the book is correct. \[\dfrac{-b \pm \sqrt{b^2-4ac}}{2a}\] \[w^2+6w-15120\] \[\dfrac{-6 \pm \sqrt{6^2-4(1)(-15120}}{2(1)}\] remember that a negative times a negative is a positive.

    • 7 months ago
  28. madsmckell
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    wow thanks soooo mcuh!! you are AMAZZZZINNNGGG!!!!

    • 7 months ago
  29. gypsy1274
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    Your Welcome!

    • 7 months ago
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