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madsmckell
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word problem!! A parcel of land is 6ft longer than it is wide. Each diagonal from one corner to the opposite corner is 174 ft long. What are the dimensions of the parcel?
 11 months ago
 11 months ago
madsmckell Group Title
word problem!! A parcel of land is 6ft longer than it is wide. Each diagonal from one corner to the opposite corner is 174 ft long. What are the dimensions of the parcel?
 11 months ago
 11 months ago

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gypsy1274 Group TitleBest ResponseYou've already chosen the best response.1
Draw a picture. That will help you figure out what to do.
 11 months ago

OpenSessame Group TitleBest ResponseYou've already chosen the best response.0
dw:1377832287651:dw
 11 months ago

madsmckell Group TitleBest ResponseYou've already chosen the best response.0
thanks but how do I solve it?
 11 months ago

gypsy1274 Group TitleBest ResponseYou've already chosen the best response.1
It is 6 feet longer than it is wide, so you can write an expression for both the length and the width.
 11 months ago

madsmckell Group TitleBest ResponseYou've already chosen the best response.0
okay.... i did that... then what?:)
 11 months ago

gypsy1274 Group TitleBest ResponseYou've already chosen the best response.1
Use the Pythagorean theorem.
 11 months ago

gypsy1274 Group TitleBest ResponseYou've already chosen the best response.1
dw:1377832617688:dw
 11 months ago

madsmckell Group TitleBest ResponseYou've already chosen the best response.0
so... (w+6)^2+w^2=174^2??????
 11 months ago

gypsy1274 Group TitleBest ResponseYou've already chosen the best response.1
Exactly.
 11 months ago

gypsy1274 Group TitleBest ResponseYou've already chosen the best response.1
Solve for w.
 11 months ago

madsmckell Group TitleBest ResponseYou've already chosen the best response.0
okay i will tryyyy
 11 months ago

gypsy1274 Group TitleBest ResponseYou've already chosen the best response.1
You can do it! I have faith in you!!
 11 months ago

madsmckell Group TitleBest ResponseYou've already chosen the best response.0
i was trying to solve for w but i got stuck... will someone help me and walk me through it??
 11 months ago

gypsy1274 Group TitleBest ResponseYou've already chosen the best response.1
Stuck where? Show your steps and I will help you?
 11 months ago

madsmckell Group TitleBest ResponseYou've already chosen the best response.0
(w+6)^2+w^2=30276..... w^2+12w+36+w^2=30276......2w^2+12w+36=30267
 11 months ago

madsmckell Group TitleBest ResponseYou've already chosen the best response.0
and now im stuck
 11 months ago

madsmckell Group TitleBest ResponseYou've already chosen the best response.0
i was trying to use the quadratic formula but i wasnt sure what to do and my numbers were wayyyyyy big
 11 months ago

gypsy1274 Group TitleBest ResponseYou've already chosen the best response.1
Great job! Find a calculator, you are going to need it. :) The quadratic formula is what you will need. I'm still working through it. Before you get to that, get all terms to the left side of the equation and set it equal to 0.
 11 months ago

gypsy1274 Group TitleBest ResponseYou've already chosen the best response.1
The numbers do get big, but you can handle it, with your calculator's help.
 11 months ago

madsmckell Group TitleBest ResponseYou've already chosen the best response.0
when i do the quadratic inside the root is negative so how would i simplify it??? isnt the quadratic formula b plus or minus the root of b^24ac all over 2a
 11 months ago

gypsy1274 Group TitleBest ResponseYou've already chosen the best response.1
It is not negative. You dropped a negative on the floor....look around, I'm sure it is still nearby. :)
 11 months ago

gypsy1274 Group TitleBest ResponseYou've already chosen the best response.1
One you get all the terms to the left side, the constant term will be negative.
 11 months ago

gypsy1274 Group TitleBest ResponseYou've already chosen the best response.1
I divided the whole equation by 2 to keep the numbers smaller. \(w^2+6w15120\)
 11 months ago

madsmckell Group TitleBest ResponseYou've already chosen the best response.0
but when you put in 15120 it is negative in the root soo it wont workkk
 11 months ago

madsmckell Group TitleBest ResponseYou've already chosen the best response.0
the answer in the back of the book is 120 by 126
 11 months ago

madsmckell Group TitleBest ResponseYou've already chosen the best response.0
so still not sure how that works when what ever i root comes out to be a decimal
 11 months ago

gypsy1274 Group TitleBest ResponseYou've already chosen the best response.1
The answer in the back of the book is correct. \[\dfrac{b \pm \sqrt{b^24ac}}{2a}\] \[w^2+6w15120\] \[\dfrac{6 \pm \sqrt{6^24(1)(15120}}{2(1)}\] remember that a negative times a negative is a positive.
 11 months ago

madsmckell Group TitleBest ResponseYou've already chosen the best response.0
wow thanks soooo mcuh!! you are AMAZZZZINNNGGG!!!!
 11 months ago

gypsy1274 Group TitleBest ResponseYou've already chosen the best response.1
Your Welcome!
 11 months ago
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