anonymous
  • anonymous
*FOR A MEDAL* Simplify. (4x – 3)(2x^2 – 7x + 1) (x^2 + 4x – 3)(2x^2 + x + 6)
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
Two different problems? Simplifying both?
anonymous
  • anonymous
yes
anonymous
  • anonymous
Okay. For the first one: This is the equation? \[(4x-3)(2x^2-7x+1)\]

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anonymous
  • anonymous
yes
anonymous
  • anonymous
You just multiply each term: First (4x)(2x^2-7x+1). This equals: 8x^3-28x^2+4x
anonymous
  • anonymous
Do you understand what I'm doing?
anonymous
  • anonymous
Then (-3)(2x^2-7x+1): -6x^2+21x-3
anonymous
  • anonymous
Subtract this from the first equation: 8x^3-28x^2+4x - (-6x^2+21x-3)
anonymous
  • anonymous
@babyblue123 Do you know how to go from there?
anonymous
  • anonymous
nope i don't get it
anonymous
  • anonymous
You're just distributing 4x-3. So you multiply it by 2x^2-7x+1.
anonymous
  • anonymous
|dw:1377833483945:dw|
anonymous
  • anonymous
oh ok
anonymous
  • anonymous
You should get 8x^3-22x^2-17x+3
anonymous
  • anonymous
Do you get what I did for the first steps?
anonymous
  • anonymous
yes
anonymous
  • anonymous
Okay :)
anonymous
  • anonymous
that's it?
anonymous
  • anonymous
@jayy2014
anonymous
  • anonymous
Oh! I forgot the second one.
anonymous
  • anonymous
Sorry, sorry. (x^2 + 4x – 3)(2x^2 + x + 6) Again, multiply each and you should get: 2x^4 + 9x^3 + 4x^2 + 21x - 18
anonymous
  • anonymous
Those are the answers.
anonymous
  • anonymous
thank you so much!

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