anonymous
  • anonymous
A pebble is dropped into a graduated cylinder and the volume rises from 25.0 mL to 31.0 mL. The mass of the pebble is 3.5g. What is the density of the pebble?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
the difference is 6
anonymous
  • anonymous
d=m/v so you do 3.5 over what
anonymous
  • anonymous
thanks @abb0t ......

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abb0t
  • abb0t
Ok, so density = \(\frac{mass}{volume}\)
abb0t
  • abb0t
But notice that you have two volumes. So that means, find the difference in the volume (meaning to subtract). That will give you the approximate volume of the pebble to use to find density.
abb0t
  • abb0t
Does that make sense? And volume cannot be negative! Reemember that. So you are taking the bigger volume and subtracting the lesser volume.
anonymous
  • anonymous
once you find the difference how do you use it in the equation?
anonymous
  • anonymous
the difference is 6 so do i do 3.5/6 ?
abb0t
  • abb0t
I will use \(D\) to represent density. D = \(\frac{3.5}{31.0-25.0}\)
abb0t
  • abb0t
Yes
anonymous
  • anonymous
so its 0.583
abb0t
  • abb0t
That is your final answer.
anonymous
  • anonymous
Thank you @abb0t !!!!!!

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