anonymous
  • anonymous
calculus I homework. please help!
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
Find y when \[2^{x}=32^{y}, 32^{x}=16^{y+1}\]
anonymous
  • anonymous
these are my answer choices 1. y =5/21 2. y =1/7 3. y =2/21 4. y =4/21 5. y =2/7
dan815
  • dan815
|dw:1377841413596:dw|

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More answers

zzr0ck3r
  • zzr0ck3r
\[32=2^5\\16^{y+1}=32^x=(2^5)^x=(2^x)^5=(32^y)^5=(32)^{5y}\\so\\16^{y+1}=32^{5y}\\2^{4(y+1)}=2^{10y}\\4y+4=25y\\21y=4\\y=\frac{4}{21}\]
dan815
  • dan815
|dw:1377841437083:dw|
zzr0ck3r
  • zzr0ck3r
my way is cleaner and done, stop messing it all up:P
dan815
  • dan815
|dw:1377841482349:dw|
zzr0ck3r
  • zzr0ck3r
...
dan815
  • dan815
|dw:1377841522003:dw|
dan815
  • dan815
bahahahah
zzr0ck3r
  • zzr0ck3r
@pancakeslover if you can get through all that mess, can you understand my pretty math?
zzr0ck3r
  • zzr0ck3r
:P
zzr0ck3r
  • zzr0ck3r
\[32=2^5\\16^{y+1}=32^x=(2^5)^x=(2^x)^5=(32^y)^5=(32)^{5y}\\so\\16^{y+1}=32^{5y}\\2^{4(y+1)}=2^{25y}\\4y+4=25y\\21y=4\\y=\frac{4}{21}\]
zzr0ck3r
  • zzr0ck3r
typo:)
dan815
  • dan815
U SEE!!!
dan815
  • dan815
GIVE ME A MEDAL NOW
zzr0ck3r
  • zzr0ck3r
lol I swear I already hit the button
dan815
  • dan815
=]
anonymous
  • anonymous
fellas! both of yall's math is beautiful. I appreciate both of them very much
abb0t
  • abb0t
This is calculus??
anonymous
  • anonymous
yup

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