CGGURUMANJUNATH
  • CGGURUMANJUNATH
\int { mg\cos { \theta } d\theta } =\int { mR\ddot { \theta } } d\theta
Mathematics
  • Stacey Warren - Expert brainly.com
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schrodinger
  • schrodinger
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CGGURUMANJUNATH
  • CGGURUMANJUNATH
\[\int\limits { mg\cos { \theta } d\theta } =\int\limits { mR\ddot { \theta } } d\theta \]
CGGURUMANJUNATH
  • CGGURUMANJUNATH
integrate wrt theta ,theta dot and theta double dot. i will give medal .can aby body help.
anonymous
  • anonymous
What math is this? This looks really hard.

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More answers

CGGURUMANJUNATH
  • CGGURUMANJUNATH
integration @asdfasdf54514
Lukecrayonz
  • Lukecrayonz
@satellite73
ash2326
  • ash2326
\[\int mg \cos \theta d\theta\] mg are constant with respect to theta, bring them out \[mg\int \cos \theta d\theta\] can you integrate it now? @CGGURUMANJUNATH
CGGURUMANJUNATH
  • CGGURUMANJUNATH
my question is can u integtate lhs and rhs wrt theta ? @ash2326
anonymous
  • anonymous
is it the original question ?
CGGURUMANJUNATH
  • CGGURUMANJUNATH
s
ash2326
  • ash2326
yes, you can do that
CGGURUMANJUNATH
  • CGGURUMANJUNATH
can u show me the steps or draw which ever is convenient to u @ash2326
UnkleRhaukus
  • UnkleRhaukus
the m's will cancel
ash2326
  • ash2326
\[\int\limits { mg\cos { \theta } d\theta } =\int\limits { mR\ddot { \theta } } d\theta\] \[mg\int \cos \theta d\theta=mR\int \ddot \theta d\theta\] We know that \[\frac{d}{d\theta} \dot \theta=\ddot \theta\] so \[mg\int \cos \theta d\theta=mR\dot \theta +C\] where C is constant, I think you can integrate the left side, can't you?
anonymous
  • anonymous
the dots are wrt to t or theta ?!
anonymous
  • anonymous
usually dots mean derivative with respect to time
CGGURUMANJUNATH
  • CGGURUMANJUNATH
ok @ash2326 u have integrated wrt theta right ?
CGGURUMANJUNATH
  • CGGURUMANJUNATH
can u integrate wrt theta dot.
ash2326
  • ash2326
yes, cause we have dtheta in the equation. No info about time
CGGURUMANJUNATH
  • CGGURUMANJUNATH
no
CGGURUMANJUNATH
  • CGGURUMANJUNATH
no information is given wrt time.
anonymous
  • anonymous
@CGGURUMANJUNATH are the dots mean derivative with respect to theta or with respect to time ?
CGGURUMANJUNATH
  • CGGURUMANJUNATH
theta @Coolsector
anonymous
  • anonymous
ok.
CGGURUMANJUNATH
  • CGGURUMANJUNATH
can u show me the steps plz @Coolsector
anonymous
  • anonymous
what steps ? if you say that the dots are with respect to theta then see the solution ash gave you
CGGURUMANJUNATH
  • CGGURUMANJUNATH
ok what ash has done wrt theta is fine ,can u integrate wrt theta dot.
CGGURUMANJUNATH
  • CGGURUMANJUNATH
@Coolsector
CGGURUMANJUNATH
  • CGGURUMANJUNATH
theta dot =\dot { \theta }
CGGURUMANJUNATH
  • CGGURUMANJUNATH
\[\dot { \theta } \]
CGGURUMANJUNATH
  • CGGURUMANJUNATH
i meant.
CGGURUMANJUNATH
  • CGGURUMANJUNATH
my question is can u integtate lhs wrt theta and rhs wrt theta dot ;is it possible to do that ?
anonymous
  • anonymous
you mean in case your original equation: mgcos(theta) = mR* (theta double dot ) ?
anonymous
  • anonymous
if so you cant integrate like this one side wrt to one varible and the other wrt to another
CGGURUMANJUNATH
  • CGGURUMANJUNATH
thank you very much @Coolsector @ash2326 and @UnkleRhaukus
anonymous
  • anonymous
anyway. i still cant get it. if dot means derivative with respect to theta then theta dot should be 1.
anonymous
  • anonymous
it is like taking the derivative of x wrt to x. and the second derivative would be 0.
CGGURUMANJUNATH
  • CGGURUMANJUNATH
it is like taking the derivative of x wrt to x.YES IT IS RIGHT, then theta dot should be 1. HOW @coolsector.
CGGURUMANJUNATH
  • CGGURUMANJUNATH
@Coolsector @ash2326 @UnkleRhaukus chech out the attachment.
1 Attachment
CGGURUMANJUNATH
  • CGGURUMANJUNATH
sorry check not chech this was the actual problem .
UnkleRhaukus
  • UnkleRhaukus
well the derivative shold be with respect to time as @Coolsector sugessted.
CGGURUMANJUNATH
  • CGGURUMANJUNATH
ok.

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