anonymous
  • anonymous
Given the graph of the function f(x) construct the slope field to sketch the graph of the anti derivative F(x) that passes through the point (0,-1)
Mathematics
  • Stacey Warren - Expert brainly.com
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katieb
  • katieb
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anonymous
  • anonymous
|dw:1377843203281:dw|
anonymous
  • anonymous
is the deriative graph.
anonymous
  • anonymous
how do i make a slope field?

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anonymous
  • anonymous
@skay here is what we do. We draw a graph with x and y the top graph is the slope, the number you pick off is the slope, so at x=0, the slope is zero a line with a slope of zero is a horizontal line. We sketch in the start of a set of lines with a slope of zero along the y-axis. then at x=1, the slope is 1, that is a 45 degree line we put in a little piece of line at 45 degrees|dw:1377859155775:dw|
anonymous
  • anonymous
at x = 2 slope is still 1, I'm going to shift the little segments up so we can fill in the cures later back to a slope of zero at x=3 down to a slope of -1, I can't quite tell what x is there a slope of -1 is a 45 degree line going down and back to zero
anonymous
  • anonymous
|dw:1377859448322:dw|
anonymous
  • anonymous
then you connect the segments with smooth curves, it would look something like what is on the whiteboard. Then you go back and pick of the line that goes through (0,-1)
anonymous
  • anonymous
|dw:1377859547147:dw|
anonymous
  • anonymous
|dw:1377859677575:dw|
anonymous
  • anonymous
Ok I just drew it again, so its a bit clearer.
anonymous
  • anonymous
|dw:1377860007193:dw|
anonymous
  • anonymous
then you pick off the line that goes through the point (0,-1) and put that on it's own graph, it would look something like that, you can probably do a better graph on your paper.lol that is it:) that is the anti-derivative F(x) that goes through (0,-1) Hope I helped you! :D
anonymous
  • anonymous
all your doing is making a graph that has the correct slope at each x location.

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