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tigeranime
An original rectangle has a length of 14 and a width of 12 . What happens to the area if the new width is double the original width? Verify your answer
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\[Old Triangle: 14*12*(1/2)\]
\[NewTriangle: 14*24*(1/2)\]
To find the area of a triangle you do width*height*(1/2)
@OpenSessame He/She is talking about a Rectangle. :)
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We start with L=14 and W=12 and now we are doubling width, so it's 24 what would be new area with l=4 and w=24?
do you recall how to find area of rectangle in general? what would be 24 times 14 then?
my mind it blank i dont under stand
Ok well, that is the only way I can help. If you're unable to understand my explanation then sorry no can do.
ok thx i will try to work on it more and see what i can come up woith thanks for you help
Just let the bass cannon kick it... JK :P sorry for saying something unrelated. XD
http://www.aaamath.com/geo78_x3.htm Remember base is just another word for width
Well, we started with dimensions 14 and 12 we found it's area to be 168 then we doubled width so we have 14 and 24 and the area of that was 336. if you compare both areas; 168 and 336 one is 2 times the other, 336 is 2 times larger than 168. so by doubling the width, our new area is also doubled. Do you understand it now? @tigeranime
doubling width also led to doubling the area, no worries. :)