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@E.ali please don't provide answers..it is against the CoC, let @hartnn do his magic here :P
you can check by plugging in each point.... like if you had to check, 2,3 in y > x+7 you would take y=3 and x= 2 and plug it in y >x+7 so, 3 > 2+7 ----> 3>9 is false, so point 2,3 does NOT lie in the solution set
you can also solve this system of equations using elimination or substituion. I suggest elimination for this one y>-3x+3 y>x+2 these become... y>-3x+3 y>3x+6
Its just soo confusing to me. I'm new at this type of algebra.
Okay, in that case I believe it may be helpful to use elimination. DO you know what that is?
Sort of, But not fluently. I really need just a good explanation.
so you can multiply the equation by a figure that you want to "eliminate" in the other equation (I multiplied by 3 because 3x can eliminate -3x). So I multiplied everyting by 3, getting an equation of y=3x+6. Do you know how to solve from there?
I guess i can figure it out from here. Thanks for the help.
hey no problem :) but would you mind showing me how you would go about solving this so I can know if you understand or not? if you don't mind, I just want you to have a good idea on how to solve these types of problems so you can do them on your own in the future!
So how would you solve when your problem looks like this: y>-3x+3 y>3x+6
take your time :)
3y on the bottom .....
This isn't my type of algebra. I give up. I appreciate you trying to help.
y > -3x + 3 y > x + 2 y > -3x + 3 3y > 3x + 6
oh yeah lol :P sorry XD i said that in my explanation but then.. i completely neglected to type the 3
the "dbl chk" method is the simplest to use on a multiple choice assignment.
Never heard of that.
whenever you obtain a solution from some process, the last step is to double check to see if it is correct
you do that by plugging the values you get back into the original equation ....
Oh double check method. i see.
Hey friends !!! It is not so hard . It is very easy !!! You just should take numbers on x , y , and ... . !!!! and you have a easy problem!
huh i never solved it that way before... seems really effecient and wow i learned something new today! :)
I still don't get it....
spose im solving for this: x + 3 = 9 , but in my haste i make a mistake and come to x=-6. To determine if there is an error or not, I dbl chk it: -6+3 = 9 is false, so that means I would have made some error along the way :)
@shaytay :! ask my questions ! Ok ?!
spose I came to the end of my work and had: y > -3x + 3 y > x + 2 (-2, -5) as a solution; did I make a mistake? lets double check it. -5 > -3(-2) + 3 -5 > (-2) + 2 is either one of these false? if so, then that has to be a wrong solution. If they are both true, then it has to be a good solution.
I don't understand any of this.. Nothing.. I really need the answer and an explanation on how you got that answer for me to get it. I'm new at this so i don't know what you guys are talking about. I never heard of the elimination method or any of this. I really appreciate you guys trying to make me understand. But i can't answer any of the questions you are asking me, its making me feel bad.
Our rules prevent us from just doing all the work for you. We need you to participate in the solution process ... even if you answer our questions incorrectly, we can then at least have some idea how to proceed is all.
Then i guess i can't get the help i need on here. Thanks anyways.