anonymous
  • anonymous
There is a circle with an 8-foot chord. The midpoint of the chord is located 3 feet from the center of the circle. What is the length of the diameter of the circle?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
Have you read the properties of circles and the Pythagoras' theorem ?
anonymous
  • anonymous
yes math is not my subject
anonymous
  • anonymous
you want the method straight-away ?

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anonymous
  • anonymous
i just need help
anonymous
  • anonymous
let me draw the fig for you |dw:1377867331768:dw|
anonymous
  • anonymous
ok
anonymous
  • anonymous
according to a property , the perpendicular bisector of any chord in the circle passes through the centre of the circle. So, the triangle here is a right-angled triangle. Now, can you solve ?
anonymous
  • anonymous
no
anonymous
  • anonymous
yes
anonymous
  • anonymous
is it 8
anonymous
  • anonymous
Now, we can apply the Pythagoras' theorem to this triangle and find out value of r. Then our diameter would be d = 2 x r
anonymous
  • anonymous
|dw:1377867960274:dw|
anonymous
  • anonymous
it's not 8. Can you write the Pythagoras' formula ?
anonymous
  • anonymous
its 11
anonymous
  • anonymous
The formula is : \[h^2 = p^2 + b^2\] where h= hypotenuse of the right traingle, and p, b the perpendicular and base respectively. So, here p=4, b=3 then can you find h,( or as in our case r ) ?
anonymous
  • anonymous
Ask me if you didn't get the explanation .
anonymous
  • anonymous
well, you're not responding. \[r = \sqrt{4^2 +3^2}\]\[ r = \sqrt{25} = 5\]So, the ans is dia = 2x5 ft =10 ft
anonymous
  • anonymous
thanks

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