anonymous
  • anonymous
simplify f(x) = 3x^2-4x+1/3x-1 Part 2: Using complete sentences, explain why f(1) = 0, f(0) = -1, and f(-1) = -2, yet f(one-third) is undefined. Be sure to show your work. (4 points)
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
chestercat
  • chestercat
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
\[f(x)=\frac{3x^2-4x+1}{3x-1}\] right?
anonymous
  • anonymous
First of all, I think you forgot the parentheses and the actual equation is (3x^2-4x+1)/(3x-1). Make sure to put parentheses because you have to follow the order of parentheses, exponents, multiply/divide, and add/subtract when solving an equation. f(1) = 0 because if you plug in x=1 for the equation f(x)=(3x^2-4x+1)/(3x-1) it becomes f(1)=(3(1)^2-4(1)+1)/(3(1)-1) which becomes (3-4+1)/(3-1) which becomes 0/3 which is 0. f(0) = -1 because if you substitute in x=0 into the equation, it becomes (3(0)^2-4(0)+1)/(0-1) which becomes 1/-1 which is -1 f(-1) = -2 because once again if you plug x=-1 into the original equation you get (3(-1)^2-4(-1)+1)/3(-1)-1 which becomes (3+4+1)/(-3-1) which becomes 8/-4 which is -2 For this one I think you meant to write that f(1/3) is undefined because if x=1/3, then the denominator of the equation (3x-1) becomes zero and it is impossible to divide and number by zero. Therefore f(1/3) is undefined
anonymous
  • anonymous
right

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
\(f(1)=0\) because if you replace \(x\) by \(0\) you get \[f(x)=\frac{3\times 1^2-4\times 1+1}{3\times 1-1}=\frac{0}{2}=0\]
anonymous
  • anonymous
similarly \(f(-1)=0\)
anonymous
  • anonymous
oops i meant to write \[f(1)=\frac{3\times 1^2-4\times 1+1}{3\times 1-1}=\frac{0}{2}=0\]
anonymous
  • anonymous
and \(f(\frac{1}{3})\) is undefined, because the denominator would be \(3\times \frac{1}{3}-1=1-1=0\) and you cannot divide by \(0\)
anonymous
  • anonymous
Thanks

Looking for something else?

Not the answer you are looking for? Search for more explanations.