simplify f(x) = 3x^2-4x+1/3x-1
Part 2: Using complete sentences, explain why f(1) = 0, f(0) = -1, and f(-1) = -2, yet f(one-third) is undefined. Be sure to show your work. (4 points)
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First of all, I think you forgot the parentheses and the actual equation is (3x^2-4x+1)/(3x-1). Make sure to put parentheses because you have to follow the order of parentheses, exponents, multiply/divide, and add/subtract when solving an equation.
f(1) = 0 because if you plug in x=1 for the equation f(x)=(3x^2-4x+1)/(3x-1) it becomes f(1)=(3(1)^2-4(1)+1)/(3(1)-1) which becomes (3-4+1)/(3-1) which becomes 0/3 which is 0.
f(0) = -1 because if you substitute in x=0 into the equation, it becomes (3(0)^2-4(0)+1)/(0-1) which becomes 1/-1 which is -1
f(-1) = -2 because once again if you plug x=-1 into the original equation you get (3(-1)^2-4(-1)+1)/3(-1)-1 which becomes (3+4+1)/(-3-1) which becomes 8/-4 which is -2
For this one I think you meant to write that f(1/3) is undefined because if x=1/3, then the denominator of the equation (3x-1) becomes zero and it is impossible to divide and number by zero. Therefore f(1/3) is undefined