anonymous
  • anonymous
The figure below shows two congruent triangular parks. What equation would help you to solve for the side length of BC and EF? Explain your reasoning using complete sentences.
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
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anonymous
  • anonymous
PLEASE HELP!!
Luigi0210
  • Luigi0210
Welcome to Openstudy :)

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anonymous
  • anonymous
Thanks:)
anonymous
  • anonymous
I seiriously need help....are you good at geometry? Not trying to offend you or anything, just asking
Luigi0210
  • Luigi0210
Geometry was never my favorite subject.. but I can always try. I would start off by setting the two equations equal to each other
anonymous
  • anonymous
ok......gimme a sec...
anonymous
  • anonymous
would it be x = 7??
Luigi0210
  • Luigi0210
Yup, that's what x would be, now what you do is plug that back in to get the side lengths
anonymous
  • anonymous
Ok....one sec..
anonymous
  • anonymous
the side lengths would be 6 right? Thats what I got.
anonymous
  • anonymous
by the way i have one more question after this...
Luigi0210
  • Luigi0210
Yup, and alright shoot.
anonymous
  • anonymous
Determine if the two figures are congruent and explain your answer. If they are congruent, tell which rigid motions were used.
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anonymous
  • anonymous
Thats my last one.
nincompoop
  • nincompoop
you have to identify each of the segment's coordinates first
anonymous
  • anonymous
Ok....so d = -2, 6 q = -4, 4 b = -3, 2 and a = -1, 1 Then for the second one h = 3, 5 g = 5, 3 f = 4, 1 e = 2, 0 now what?
anonymous
  • anonymous
Don't leave me!
nincompoop
  • nincompoop
I am here. can you calculate the distance of each segments and see if anything matches from figure one (right side) and figure two (left side
anonymous
  • anonymous
What do you mean cauculate the distance?
nincompoop
  • nincompoop
do you know the distance formula?
nincompoop
  • nincompoop
if not, you can derive it from pythagorean theorem.
anonymous
  • anonymous
Ummm.... what? sorry but this is why I needed help I dont remember.
anonymous
  • anonymous
Wouldn't counting the spaces work?
anonymous
  • anonymous
like counting from point d to point a. you go one to the right and 5 down. If you do the same from point H to point E it works too.
nincompoop
  • nincompoop
|dw:1377879469089:dw|
nincompoop
  • nincompoop
of course that works, but you want to be able to show it mathematically right?
anonymous
  • anonymous
I guess so, but it just says determine if the figures are congruent and expalin how you did it.
anonymous
  • anonymous
I mean explain
nincompoop
  • nincompoop
the explanation would be by means of mathematical procedure - by calculating each segment's length or what we normally refer to as distance.
anonymous
  • anonymous
Ok so I just do that for one side and then the corresponding side?
anonymous
  • anonymous
Or all of them?
nincompoop
  • nincompoop
exactly. it's a long work, but you get to practice a lot by the end of it.
nincompoop
  • nincompoop
you want to be able to do it strategically. look at the possible longest sides of each figure. calculate their distances and see if it matches.
anonymous
  • anonymous
ok, wait juuuuust a minute
anonymous
  • anonymous
ok, i did it for line DA and Line HE and Line DA came out to be sqrt(26) and Line HE was sqrt(10) so they aren't congruent?
anonymous
  • anonymous
Hello?
nincompoop
  • nincompoop
are you sure? show me your calculation
anonymous
  • anonymous
d = sqrt (( -1 - -2) ^2 + (1 - 6)^2) d = sqrt ((1)^2 + (-5)^2 d = 1 + 25 d = 26 That was line DA is that one right?
nincompoop
  • nincompoop
|dw:1377880353324:dw| |dw:1377880596464:dw||dw:1377880706364:dw|
anonymous
  • anonymous
OHHHHHHHH! I feel so stupid....I see it now...so they are congruent that much I understand, but I cannot figure out what transformations took place for that shape to get there... help me with that and I'll leave you alone ;)
nincompoop
  • nincompoop
http://www.mathsisfun.com/geometry/transformations.html
nincompoop
  • nincompoop
|dw:1377881059785:dw|
anonymous
  • anonymous
ambulance... and I didn't need a mirror:0
anonymous
  • anonymous
I thought refelction at first too, but it would have to be a combination of both translation and reflection since it isn't exactly a mirror image on the other side. it's touching the x axis whereas the other one isnt
nincompoop
  • nincompoop
the instruction was important for you to follow… that's how you will make the connection between the word I gave you and the shapes you were given.
anonymous
  • anonymous
I get your point but read my previous post
nincompoop
  • nincompoop
In Geometry, "Translation" simply means Moving ... ... without rotating, resizing or anything else, just moving. http://www.mathsisfun.com/geometry/translation.html you didn't read the contents of the first link I gave you - this http://www.mathsisfun.com/geometry/transformations.html
anonymous
  • anonymous
I did read it... but the reflection isn't and exact mirror image thats what i'm trying to say. If it was an exact mirror image, the only difference between the shapes would be the fact that the x coordinates would be the same numbers, just positive.
anonymous
  • anonymous
I'm not telling you you're wrong, I'm just voicing my opinion.
nincompoop
  • nincompoop
http://www.mathsisfun.com/geometry/reflection.html
anonymous
  • anonymous
if you insist, Thanks a bunch!
nincompoop
  • nincompoop
the reflection line can be at any direction
anonymous
  • anonymous
Ok thanks:) You helped a lot:) God bless.
nincompoop
  • nincompoop
so you want to say it's a combination of reflection and transformation?
nincompoop
  • nincompoop
I mean translation
anonymous
  • anonymous
I did, but I've already submitted my assignment. Thanks again!
nincompoop
  • nincompoop
always trust your self and if it turns out wrong, then learn from it. that's what I do at least in math.
anonymous
  • anonymous
That's true...good words to live by:) Closing question.

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