anonymous
  • anonymous
How would I rewrite the conic sections by completing the square? X^2-6x+y^2+14y-62=0
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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Luigi0210
  • Luigi0210
Group terms and then move the number to the other side
Luigi0210
  • Luigi0210
First of all, do you know what conic this is?
anonymous
  • anonymous
No

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anonymous
  • anonymous
https://www.khanacademy.org/math/algebra/conic-sections/conic_basics/v/introduction-to-conic-sections
anonymous
  • anonymous
this is good for an overview
anonymous
  • anonymous
Okay. Thankyou
anonymous
  • anonymous
Okay so now I have x^2-6x+y^2+14y=62
Luigi0210
  • Luigi0210
Yup, so now complete the square
Luigi0210
  • Luigi0210
@OffnenStudieren will help you from here
anonymous
  • anonymous
hmm, one second
anonymous
  • anonymous
Okay
anonymous
  • anonymous
\[x ^{2}-6x+y^{2}+14y=62\]
anonymous
  • anonymous
Thats what I got but I don't know how to complete the square though
anonymous
  • anonymous
http://answers.yahoo.com/question/index?qid=20090818092940AAO4RJI Look at this example
anonymous
  • anonymous
I am good at finding resources, but I am not necessarily good at the actual math...
anonymous
  • anonymous
Is there another resource. I am struggling with this one
anonymous
  • anonymous
one second
anonymous
  • anonymous
http://www2.moundsviewschools.org/irondale/userfiles/kountzj/ch12conics/morecompleteingsquare.pdf scroll down to page three

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