At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
you forgot the negative 5y = -3x + 9
Sosa that was a bit confusing though
Oh my. Not only DON'T give answers, but for God's sake, don't give WRONG answers, as both of the above answerers did.
Debbie can you help then please?
@Bacon , just solve the equation for y. @AlmightySosa300 was close, but just forgot that you have to SUBTRACT the 3x from both sides, so it becomes negative on the RHS.
sorry guyz...i thought it was asked in intercept form only
3x+5y=9 Subtract 3x from both sides. Then divide both sides by the coefficient on y (the 5). That will isolate y, once you have y=mx + b, that's your slope-intercept form.
3x+ 5y=9 we will have to make in the form of y=mx+c that is 5y=9-3x y=(9-3x)/5 y = (9/5)+(-3/5)x y=c+mx
so erm would the b be a fraction then?
or c in viveks case
Yes, you'll get a fraction for both the y-intercept and the slope. That's ok, some lines are just like that. :)
Btw, your username and pic are cracking me up.
so would these be the steps then? 3x+5y=9 5y=3x+9 5y=9?
and then y=9/5
Woah.... first off, you did not SUBTRACT the 3x on the right. You cant SUBTRACT it from the left but ADD IT to the right. :) So the sign is wrong. But more importantly.... WHERE DID IT GO?? It just disappeared between step 2 and step 3. It's part of the equation for the line!
y is not = a constant here, y = a function of x. The x term has to be there.
Debbie can you please just write out how you would do it so i can see where i went wrong please?
Well, I explained exactly where you went wrong. But what I WILL do is a DIFFERENT problem that is of the same type, as an example. So let's solve 5x+2y=11 for slope intercept form, which as I said, just means to "solve for y". That will give me y=mx+b 5x+2y=11 I need the y term alone, so I will SUBTRACT the term with the x from both sides: 2y=-5x+11 Now I'm almost there, just need to divide both sides by 2 (which you can, alternatively, consider as multiplying by 1/2, since that's the very same thing). Just remember that on the right side, I must DISTRIBUTE to both terms, e.g.: (1/2)*(2y)=(-5x+11)*(1/2) Which gives me: y=(-5/2)x+11/2 Slope = m = -5/2 Y-intercept = b = 11/2
@DebbieG I think i got it now thanks!!!!
so is this right? y=(=3/5)x+9/5
@Bacon GO VEGAN!
Haha @AkashdeepDeb .... @bacon, with the exception of the fact that I think you mean that to be "-" in front of the 3, not a "=", yes, that's right! Good job!