anonymous
  • anonymous
Simplify: see drawing>>>>>>>
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
|dw:1377893559501:dw|
anonymous
  • anonymous
rewrite using eponents
anonymous
  • anonymous
\[\sqrt[3]{\sqrt{576a^14/\sqrt{9a^8}}}\]

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anonymous
  • anonymous
\[\sqrt[3]{\sqrt{576a^1/\sqrt{9a^8}}}\]
anonymous
  • anonymous
|dw:1377893833939:dw|
anonymous
  • anonymous
please help!!!!!!!!!!!!!!!
anonymous
  • anonymous
no the roots
anonymous
  • anonymous
ok one moment
anonymous
  • anonymous
but you can simplify, so I'd suggest doing that first
anonymous
  • anonymous
the bottom is 3
anonymous
  • anonymous
(3)(3)=9
anonymous
  • anonymous
one moment
anonymous
  • anonymous
nothing goes into 576
anonymous
  • anonymous
oh, really? 5+7+6=18 so it's divisible by 9
jdoe0001
  • jdoe0001
5 + 7 + 6 = 18 well, well well, what do you know, is divisible by 3 as well
anonymous
  • anonymous
(3)(3)(3)(3)=729
jdoe0001
  • jdoe0001
hmm \(\bf 3^4 = 81\)
anonymous
  • anonymous
? no. 3*3*3*3 = 81
anonymous
  • anonymous
ok
anonymous
  • anonymous
I'm working on 576
anonymous
  • anonymous
576a^6
anonymous
  • anonymous
9a
jdoe0001
  • jdoe0001
lemme start off 576, and you finish it|dw:1377894809203:dw|
anonymous
  • anonymous
32 2
anonymous
  • anonymous
16 2
jdoe0001
  • jdoe0001
then you still have 32, which is still diviisible you divide the result until is not longer divisible
anonymous
  • anonymous
8 2
anonymous
  • anonymous
4 2 2 2
anonymous
  • anonymous
2*2
anonymous
  • anonymous
2a^6
jdoe0001
  • jdoe0001
|dw:1377895073946:dw|
jdoe0001
  • jdoe0001
\(\bf 576 = 3^2 \times (2^2)^3 \implies 3^2 \times (2^3)^2\qquad \qquad \sqrt{576a^{14}} \implies \sqrt{3^2 \times (2^3)^2 a^{14}}\)
anonymous
  • anonymous
ok I understand
anonymous
  • anonymous
= 2a
anonymous
  • anonymous
do you agree???

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