anonymous
  • anonymous
simplify where i,j,k, represent the basis vectors in R^3: -2(3i-4j -5k) dot (2i+3k)+2i dot (3j-2k)
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
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Psymon
  • Psymon
Sorry bout that. Not seeing where you got your bottom result, lol.
Psymon
  • Psymon
Alright, im not gonna say anything since someone else is answering.

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anonymous
  • anonymous
oh man.. i need to review again... just say any explanation.. ..
Psymon
  • Psymon
Im just not going to talk over someone is all xD I dont like to try to answer when someone else starts typing usually >.<
anonymous
  • anonymous
oh ok...i'll just wait.
anonymous
  • anonymous
-2(3i-4j-5k).(2i+3k)+2i .(3j-2k) \[=-\left\{ \left( 3 \right)\left( 2 \right)+\left( 0 \right)+\left( -5 \right)\left( 3 \right) \right\}\]+0 =-6+15=9 i.j=j.k=i.k=0 i.i=j.j=k.k=1
anonymous
  • anonymous
@surjithayer sorry.. i cannot understand because:
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anonymous
  • anonymous
and the answer should be 18 according to the book i'm looking to..
Psymon
  • Psymon
It is 18. Now that I dont mind speaking so much *wonder if picture will copy and paste*
Psymon
  • Psymon
|dw:1377908501285:dw| d
Psymon
  • Psymon
Nope, oh well. Hang on.
anonymous
  • anonymous
ok..lol:)
Psymon
  • Psymon
(-6i+8j+10k) dot (2i +3k) (-6)(2) + (8)(0) + (10)(3) -12 + 0 + 30 = 18 18 + 2i dot (3j-2k) 18 + (2)(0) + (0)(3) + (0)(-2) 18 + 0 + 0 + 0 = 18
Psymon
  • Psymon
@Data_LG2
anonymous
  • anonymous
oohh.. is it the same as @surjithayer did??
Psymon
  • Psymon
I only understand part of what he did. He did the first dot before multiplying inthe -2. In fact, I dont know what hedid with the -2.
anonymous
  • anonymous
i wish i could see hat he did...
Psymon
  • Psymon
Yeah, he forgot to put a 2, he just put -. He did the dot product first then multiplying in the negative. If he HAD remembered the two, itd still have been wrong because you need to multiply in the -2 first before you dot.
anonymous
  • anonymous
oohh ok then.. thanks again:)
anonymous
  • anonymous
sorry i forgot to write 2
anonymous
  • anonymous
that's fine.. thanks for your help(^_^) @surjithayer
anonymous
  • anonymous
yw
anonymous
  • anonymous
@Psymon i'm just wondering what happened to 2i dot (3j-2k)?

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