anonymous
  • anonymous
For this question, you will need a parent/guardian or a friend. Have this individual grab a handful of coins making sure there are only two types of coins in the group (i.e., nickels and dimes, quarters and pennies, pennies and dimes, etc). Your parent/guardian or friend should tell you the type of coins they’ve chosen, how many coins they have and the dollar amount of the group. From this information, you will set up two sets of equations and determine how many of each coin they have in their hand. Please send your instructor the name of the individual who helped you with this question, your your two equations and the work you did to solve the system.
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
@Rexy705 can u help?
anonymous
  • anonymous
you want me to make something up?
anonymous
  • anonymous
i have 9 coins only dimes and quarters the total amount of money is $1.65 how many of each do i have?

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anonymous
  • anonymous
idk i need help @satellite73
anonymous
  • anonymous
lol @question it implies that those whose parent/guardian is no longer alive can't do the question. How terribly restricting..
anonymous
  • anonymous
ok well there is the first part i came up with a fictitious amount of dimes and quarters and a total amount of money now comes the second part, you have to figure out how many of each i have
anonymous
  • anonymous
lol @genius12 i guess i am a parent for a day
anonymous
  • anonymous
ok how?
anonymous
  • anonymous
lets put \(x\) as the number of dimes, \(y\) as the total number of quarters, and solve for \(x\) and \(y\)
anonymous
  • anonymous
i told you i had 9 coins all together how can we write that as an equation with \(x\) and \(y\) ?
anonymous
  • anonymous
x+y=9?
anonymous
  • anonymous
got it! first equation is done
anonymous
  • anonymous
now for the second one each dime is worth 10 cents, so if i have \(x\) dimes, how much money do i have in dimes (hint, if i had 13 dimes i would have 130 cents)
anonymous
  • anonymous
if it is not clear, let me know and i will tell you
anonymous
  • anonymous
90?
anonymous
  • anonymous
if i had 9 dimes i would have 90 cents, yes, but i don't have 9 dimes, i have \(x\) dimes your answer has to have an \(x\) in it
anonymous
  • anonymous
what did you do to 9 to get 90?
anonymous
  • anonymous
like i said, if it is not clear, let me know and i will tell you
anonymous
  • anonymous
did i lose you?
anonymous
  • anonymous
no
anonymous
  • anonymous
it is clear
anonymous
  • anonymous
ok so is it more or less clear that the amount of money i have in times is \(10x\) ?
anonymous
  • anonymous
am i wrong?
anonymous
  • anonymous
if i have 3 dimes i have 30 cents if i have 6 dimes i have 60 cents if i have 9 dimes i have 90 cents if i have \(x\) dimes i have \(10x\) cents
anonymous
  • anonymous
ohhhhh okay
anonymous
  • anonymous
similarly if i have 2 quarters i have 50 cents if i have 4 quarters i have 100 cents if i have 7 quarters i have 175 cents
anonymous
  • anonymous
how much if i have \(y\) quarters?
anonymous
  • anonymous
10y?
anonymous
  • anonymous
not quite \(10\) is for the dime how many pennies in a quarter?
anonymous
  • anonymous
25
anonymous
  • anonymous
25y?
anonymous
  • anonymous
right
anonymous
  • anonymous
so now the total amount of money: \(10x\) for the dimes, \(25y\) for the quarters, so the total is \[10x+25y\] which we know is \(165\) so we can say \[10x+25y=165\]
anonymous
  • anonymous
now we have two equations \[x+y=9\\10x+25y=165\] and we can solve this for \(x\)
anonymous
  • anonymous
can you help me solve?
anonymous
  • anonymous
any idea how to do it? ("no" is a find answer, i will show you if you do not)
anonymous
  • anonymous
ok i take that as a no
anonymous
  • anonymous
the first equation \(x+y=9\) is the same as saying \(y=9-x\)
anonymous
  • anonymous
then we can replace the \(y\) in the second equation \(10x+25y=165\) by \(\color{red}{9-x}\) and solve for \(x\) \[10x+25\color{red}y=165\\ 10x+25(\color{red}{9-x})=165\]
anonymous
  • anonymous
multiply out on the left to get \[10x+225-25x=165\]
anonymous
  • anonymous
collect like terms on the left to get \[-15x+225=165\]
anonymous
  • anonymous
subtract \(225\) from both sides and get \[-15x=165-225=-60\] and finally divide both sides by \(-15\) and get \[x=(-60)\div( -15)=4\]
anonymous
  • anonymous
so i have \(4\) dimes now the total was \(9\) so how many quarters do i have?
anonymous
  • anonymous
ummm 4?
anonymous
  • anonymous
total is 9 4 dimes how many quarters?
anonymous
  • anonymous
idk
anonymous
  • anonymous
i don't believe you
anonymous
  • anonymous
i"m confused
anonymous
  • anonymous
9 coins, 4 dimes, how many quarters
anonymous
  • anonymous
5?
anonymous
  • anonymous
yes
anonymous
  • anonymous
because \(9=4+5\)
anonymous
  • anonymous
now lets check the answer 5 quarters and 4 dimes is 9 coins the 5 quarters are worth $1.25 and the 4 dimes are worth $.40 for a total of $1.25+.40=1.65
anonymous
  • anonymous
oh thanks that helped a lot
anonymous
  • anonymous
yw
anonymous
  • anonymous
where is says Please send your instructor the name of the individual who helped you with this question you can put "satellite73"
anonymous
  • anonymous
lol sure

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