Could anyone help me to find the area of the following parallelogram |dw:1377920509347:dw|

- anonymous

Could anyone help me to find the area of the following parallelogram |dw:1377920509347:dw|

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- anonymous

any help any one????

- anonymous

I cannot see your drawing. The area of a parallelogram is \(base \times height\). If the sides are parallel, that would translate to \(length \times width\).

- anonymous

|dw:1377925998374:dw|

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## More answers

- anonymous

I am not sure of the sure because that measure in the middle

- anonymous

area of ||gm = base * height
here base =41 and height =22

- anonymous

so just multiply 41 and 22

- anonymous

The measure in the middle is the height.

- anonymous

902 is that it??
what is the measure of 27 out side ?

- anonymous

902 is correct. the 27 is just extra information.

- anonymous

Any line that is perpendicular to the base, is the height.

- anonymous

owwww thanks a lot .

- anonymous

Your Welcome.

- anonymous

can you help me to clarify another one??

- anonymous

Sure.

- anonymous

I will draw it

- anonymous

|dw:1377926597582:dw|

- anonymous

You have 2 shapes - find the areas separately and add them together.

- anonymous

but in this drawing I do not know what base to put in each??

- anonymous

Start with the trapezoid. Do you know the formula?

- anonymous

A= b1 + b2/2 xh is that??

- anonymous

Yes. Do you remember what I told you about how to identify the height?

- anonymous

yes

- anonymous

so h=6,12 in
b1= 12 in
b2=11,75??

- anonymous

12 is not the base of the trapezoid. |dw:1377927207210:dw|

- anonymous

ohh 18 is base 1 and 11,75 is base 2 and the other is extra information??

- anonymous

The other numbers are not extra information this time, they refer to the triangle that we will get to in a bit.

- anonymous

I sorry I just very bad at geometry at least here someone could explain me better

- anonymous

Being bad at math or geometry is a common misconception. Everything is hard until you learn how to do it.

- anonymous

So, do you have the area of the trapezoid?

- anonymous

around 91

- anonymous

That is correct. Were you told to round?

- anonymous

The next step would be to find the area of the triangle. It may help to draw the triangle separately.

- anonymous

which formula 1/2 x b x hb ??

- anonymous

1/2 base times height. You added an extra base in your formula.

- anonymous

ok

- anonymous

base =13,42 in
h =12 in

- anonymous

Yes.

- anonymous

triangle=1/2 x bx h
= 1/2 x 13,42 x 12 =80,52

- anonymous

You got it!

- anonymous

so my area of the parallelogram is 91 but I have to find the second triangle as well?

- anonymous

No, that was the area of the trapezoid.

- anonymous

oh sorry

- anonymous

There is no second triangle. The 6.12 line is indicating the height.

- anonymous

No need to apologize - with the effort you are showing, mistakes will help you learn!

- anonymous

Thanks a lot; the figure is a trapezoid and the area here is 80,52 because the measure it is show in the shadow of the figure???

- anonymous

the shadow figure?

- anonymous

The part below??

- anonymous

The top shape is the trapezoid at 91.035 and the bottom is the triangle at 80.52. Add them together and you will have the total area.

- anonymous

total area = 80,52 + 91,035 = 171,555. It is too huge or it is ok??

- anonymous

That is the answer that I got. Great Job!!

- anonymous

you deserve more than a good medal, thanks I finally understood and put in practice the concept . thanksssssssssss

- anonymous

Great! I'm glad I could help.

- anonymous

I am your biggest fan!!!!!!!!!!!!!!!! now I got to go to sleep god night.

- anonymous

Good Night!

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