anonymous
  • anonymous
Help finding the limit of a function.
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
\[\lim_{x \rightarrow 0}\frac{ 3x^2-2x+\sin 5x }{ x }\]
anonymous
  • anonymous
I know the last part (sin5x/x) should be 5, but not the rest.
Psymon
  • Psymon
Break it into 3 fractions. You can make each term in the numerator into its own fraction, being divided by the denominator.

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anonymous
  • anonymous
|dw:1377925519347:dw|
Psymon
  • Psymon
@Dido525 Another Jirachi, cute :D
anonymous
  • anonymous
That 2nd terms looks REALLY similar to lim x-> 0 sin(x)/x dosen't it?
anonymous
  • anonymous
<3 Jirachi :) .
anonymous
  • anonymous
Recall lim x-> sin(ax)/a is 1 as well.
anonymous
  • anonymous
Ah. I tried breaking into three, but it didn't work out two well. Breaking it into two looks better. Yeah, it should be 5.
anonymous
  • anonymous
How can you change the second one so it looks like that?
anonymous
  • anonymous
too*
anonymous
  • anonymous
Multiply by 5/5.
anonymous
  • anonymous
Good job :) .
anonymous
  • anonymous
I think I get it now. I didn't do a good job of breaking the limit down. Thanks for yur help Dido. I know better now.
anonymous
  • anonymous
You often have to separate it and use algebra to manipulate limits.
Psymon
  • Psymon
\[\frac{ 3x ^{2} }{ x }-\frac{ 2x }{ x }+\frac{ \sin5x }{ x }\] \[3x-2+5(\frac{ \sin5x }{ 5 })\]I dunno, I just think to do it striaght as 3 fractions, lol x_x
anonymous
  • anonymous
You will learn a trick later where you can do it without splitting it up :) .
anonymous
  • anonymous
Yeah. Thanks

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