• anonymous
A transverse wave on a string is described by the following wave function. y = 0.080 sin(π/10x + 5πt) where x and y are in meters and t is in seconds. a) Determine the transverse speed at t = 0.210 s for an element of the string located at x = 1.80 m. b) Determine the transverse acceleration at t = 0.210 s for an element of the string located at x = 1.80 m. c) What is the wavelength of this wave? d) What is the period of this wave? e) What is the speed of propagation of this wave?
  • Stacey Warren - Expert
Hey! We 've verified this expert answer for you, click below to unlock the details :)
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
  • schrodinger
I got my questions answered at in under 10 minutes. Go to now for free help!
  • ybarrap
The easy stuff first: \( \omega=5\pi\): The angular frequency \(\large T={2\pi\over\omega}\) : The period \(k=\dfrac \pi {10}\): The wave number \(\large \lambda=\large {2\pi\over k}\): The wavelength \(\nu=\large { \lambda \over T}\) or \(\nu=\large { \omega \over k}\): The speed of Propagation To determine the transverse velocity and acceleration, we need to find \(\dfrac {dy}{dx}\) and \(\dfrac {d^2y}{dx^2}\) and then substitute the values for t and x that are given. Hope this helped. Good luck.

Looking for something else?

Not the answer you are looking for? Search for more explanations.