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highschoolmom2010
 one year ago
Law of sine question :DD
highschoolmom2010
 one year ago
Law of sine question :DD

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AkashdeepDeb
 one year ago
Best ResponseYou've already chosen the best response.0Why do you have a question if you know what the law of sines is?

highschoolmom2010
 one year ago
Best ResponseYou've already chosen the best response.1im not sure if i am doing it right

cwrw238
 one year ago
Best ResponseYou've already chosen the best response.0for a triangle ABC a/ sinA = b/sinB = c/sinC

highschoolmom2010
 one year ago
Best ResponseYou've already chosen the best response.1dw:1377962024865:dw \[\frac{ \sin 80 }{ 17 }=\frac{ \sin Z }{ 14 }\]

highschoolmom2010
 one year ago
Best ResponseYou've already chosen the best response.1like that ????

highschoolmom2010
 one year ago
Best ResponseYou've already chosen the best response.114(sin 80) = 17(sin 17)

highschoolmom2010
 one year ago
Best ResponseYou've already chosen the best response.1\[\frac{ 14 \sin 80 }{ 17 }=\frac{ 17 \sin Z }{ 17 }\]

highschoolmom2010
 one year ago
Best ResponseYou've already chosen the best response.1whats where im lost

terenzreignz
 one year ago
Best ResponseYou've already chosen the best response.1^_^ You're actually doing great :) Now, 17 cancels out here: \[\frac{ 14 \sin 80 }{ 17 }=\frac{ \cancel{17} \sin Z }{ \cancel{17} }\]

terenzreignz
 one year ago
Best ResponseYou've already chosen the best response.1and we get... \[\Large \sin Z = \frac{14\sin 80^o}{17}\]

highschoolmom2010
 one year ago
Best ResponseYou've already chosen the best response.1but i plugged the remaining in calculator and got a crazy answer

highschoolmom2010
 one year ago
Best ResponseYou've already chosen the best response.10.81101814953

highschoolmom2010
 one year ago
Best ResponseYou've already chosen the best response.1that cant be right

terenzreignz
 one year ago
Best ResponseYou've already chosen the best response.1Ahh... I see. Because what you got was the SINE of the angle Z :) You have to run it through \(\large \sin^{1}\) to get the angle Z itself ^_^ \[\Large Z = \sin^{1}\left(\frac{14\sin 80^o}{17}\right)\]

highschoolmom2010
 one year ago
Best ResponseYou've already chosen the best response.1oh i forgot to do teh inverse

terenzreignz
 one year ago
Best ResponseYou've already chosen the best response.1There's your problem ^_^ I trust it no longer IS a problem? :D

highschoolmom2010
 one year ago
Best ResponseYou've already chosen the best response.1let me try that and see what i get '

terenzreignz
 one year ago
Best ResponseYou've already chosen the best response.1I'm sure it'll be more... believable... this time around ^_^

highschoolmom2010
 one year ago
Best ResponseYou've already chosen the best response.154.1955269839

terenzreignz
 one year ago
Best ResponseYou've already chosen the best response.1More reasonable, don't you think? ^_^

terenzreignz
 one year ago
Best ResponseYou've already chosen the best response.1Correct, by the way :D

highschoolmom2010
 one year ago
Best ResponseYou've already chosen the best response.1thanks for the clarification :D
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