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highschoolmom2010 Group TitleBest ResponseYou've already chosen the best response.1
 11 months ago

AkashdeepDeb Group TitleBest ResponseYou've already chosen the best response.0
Why do you have a question if you know what the law of sines is?
 11 months ago

highschoolmom2010 Group TitleBest ResponseYou've already chosen the best response.1
im not sure if i am doing it right
 11 months ago

AkashdeepDeb Group TitleBest ResponseYou've already chosen the best response.0
You are!
 11 months ago

cwrw238 Group TitleBest ResponseYou've already chosen the best response.0
for a triangle ABC a/ sinA = b/sinB = c/sinC
 11 months ago

highschoolmom2010 Group TitleBest ResponseYou've already chosen the best response.1
dw:1377962024865:dw \[\frac{ \sin 80 }{ 17 }=\frac{ \sin Z }{ 14 }\]
 11 months ago

highschoolmom2010 Group TitleBest ResponseYou've already chosen the best response.1
like that ????
 11 months ago

highschoolmom2010 Group TitleBest ResponseYou've already chosen the best response.1
14(sin 80) = 17(sin 17)
 11 months ago

highschoolmom2010 Group TitleBest ResponseYou've already chosen the best response.1
\[\frac{ 14 \sin 80 }{ 17 }=\frac{ 17 \sin Z }{ 17 }\]
 11 months ago

highschoolmom2010 Group TitleBest ResponseYou've already chosen the best response.1
whats where im lost
 11 months ago

terenzreignz Group TitleBest ResponseYou've already chosen the best response.1
^_^ You're actually doing great :) Now, 17 cancels out here: \[\frac{ 14 \sin 80 }{ 17 }=\frac{ \cancel{17} \sin Z }{ \cancel{17} }\]
 11 months ago

terenzreignz Group TitleBest ResponseYou've already chosen the best response.1
and we get... \[\Large \sin Z = \frac{14\sin 80^o}{17}\]
 11 months ago

highschoolmom2010 Group TitleBest ResponseYou've already chosen the best response.1
but i plugged the remaining in calculator and got a crazy answer
 11 months ago

terenzreignz Group TitleBest ResponseYou've already chosen the best response.1
What was it? ^_^
 11 months ago

highschoolmom2010 Group TitleBest ResponseYou've already chosen the best response.1
0.81101814953
 11 months ago

highschoolmom2010 Group TitleBest ResponseYou've already chosen the best response.1
that cant be right
 11 months ago

terenzreignz Group TitleBest ResponseYou've already chosen the best response.1
Ahh... I see. Because what you got was the SINE of the angle Z :) You have to run it through \(\large \sin^{1}\) to get the angle Z itself ^_^ \[\Large Z = \sin^{1}\left(\frac{14\sin 80^o}{17}\right)\]
 11 months ago

highschoolmom2010 Group TitleBest ResponseYou've already chosen the best response.1
oh i forgot to do teh inverse
 11 months ago

terenzreignz Group TitleBest ResponseYou've already chosen the best response.1
There's your problem ^_^ I trust it no longer IS a problem? :D
 11 months ago

highschoolmom2010 Group TitleBest ResponseYou've already chosen the best response.1
let me try that and see what i get '
 11 months ago

terenzreignz Group TitleBest ResponseYou've already chosen the best response.1
I'm sure it'll be more... believable... this time around ^_^
 11 months ago

highschoolmom2010 Group TitleBest ResponseYou've already chosen the best response.1
54.1955269839
 11 months ago

terenzreignz Group TitleBest ResponseYou've already chosen the best response.1
More reasonable, don't you think? ^_^
 11 months ago

terenzreignz Group TitleBest ResponseYou've already chosen the best response.1
Correct, by the way :D
 11 months ago

highschoolmom2010 Group TitleBest ResponseYou've already chosen the best response.1
thanks for the clarification :D
 11 months ago

terenzreignz Group TitleBest ResponseYou've already chosen the best response.1
No problem ^_^
 11 months ago
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