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AkashdeepDeb Group TitleBest ResponseYou've already chosen the best response.0
Why do you have a question if you know what the law of sines is?
 one year ago

highschoolmom2010 Group TitleBest ResponseYou've already chosen the best response.1
im not sure if i am doing it right
 one year ago

AkashdeepDeb Group TitleBest ResponseYou've already chosen the best response.0
You are!
 one year ago

cwrw238 Group TitleBest ResponseYou've already chosen the best response.0
for a triangle ABC a/ sinA = b/sinB = c/sinC
 one year ago

highschoolmom2010 Group TitleBest ResponseYou've already chosen the best response.1
dw:1377962024865:dw \[\frac{ \sin 80 }{ 17 }=\frac{ \sin Z }{ 14 }\]
 one year ago

highschoolmom2010 Group TitleBest ResponseYou've already chosen the best response.1
like that ????
 one year ago

highschoolmom2010 Group TitleBest ResponseYou've already chosen the best response.1
14(sin 80) = 17(sin 17)
 one year ago

highschoolmom2010 Group TitleBest ResponseYou've already chosen the best response.1
\[\frac{ 14 \sin 80 }{ 17 }=\frac{ 17 \sin Z }{ 17 }\]
 one year ago

highschoolmom2010 Group TitleBest ResponseYou've already chosen the best response.1
whats where im lost
 one year ago

terenzreignz Group TitleBest ResponseYou've already chosen the best response.1
^_^ You're actually doing great :) Now, 17 cancels out here: \[\frac{ 14 \sin 80 }{ 17 }=\frac{ \cancel{17} \sin Z }{ \cancel{17} }\]
 one year ago

terenzreignz Group TitleBest ResponseYou've already chosen the best response.1
and we get... \[\Large \sin Z = \frac{14\sin 80^o}{17}\]
 one year ago

highschoolmom2010 Group TitleBest ResponseYou've already chosen the best response.1
but i plugged the remaining in calculator and got a crazy answer
 one year ago

terenzreignz Group TitleBest ResponseYou've already chosen the best response.1
What was it? ^_^
 one year ago

highschoolmom2010 Group TitleBest ResponseYou've already chosen the best response.1
0.81101814953
 one year ago

highschoolmom2010 Group TitleBest ResponseYou've already chosen the best response.1
that cant be right
 one year ago

terenzreignz Group TitleBest ResponseYou've already chosen the best response.1
Ahh... I see. Because what you got was the SINE of the angle Z :) You have to run it through \(\large \sin^{1}\) to get the angle Z itself ^_^ \[\Large Z = \sin^{1}\left(\frac{14\sin 80^o}{17}\right)\]
 one year ago

highschoolmom2010 Group TitleBest ResponseYou've already chosen the best response.1
oh i forgot to do teh inverse
 one year ago

terenzreignz Group TitleBest ResponseYou've already chosen the best response.1
There's your problem ^_^ I trust it no longer IS a problem? :D
 one year ago

highschoolmom2010 Group TitleBest ResponseYou've already chosen the best response.1
let me try that and see what i get '
 one year ago

terenzreignz Group TitleBest ResponseYou've already chosen the best response.1
I'm sure it'll be more... believable... this time around ^_^
 one year ago

highschoolmom2010 Group TitleBest ResponseYou've already chosen the best response.1
54.1955269839
 one year ago

terenzreignz Group TitleBest ResponseYou've already chosen the best response.1
More reasonable, don't you think? ^_^
 one year ago

terenzreignz Group TitleBest ResponseYou've already chosen the best response.1
Correct, by the way :D
 one year ago

highschoolmom2010 Group TitleBest ResponseYou've already chosen the best response.1
thanks for the clarification :D
 one year ago

terenzreignz Group TitleBest ResponseYou've already chosen the best response.1
No problem ^_^
 one year ago
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