## highschoolmom2010 3 years ago Law of sine question :DD

1. highschoolmom2010

2. AkashdeepDeb

Why do you have a question if you know what the law of sines is?

3. highschoolmom2010

im not sure if i am doing it right

4. AkashdeepDeb

You are!

5. cwrw238

for a triangle ABC a/ sinA = b/sinB = c/sinC

6. highschoolmom2010

|dw:1377962024865:dw| $\frac{ \sin 80 }{ 17 }=\frac{ \sin Z }{ 14 }$

7. highschoolmom2010

like that ????

8. cwrw238

yes

9. highschoolmom2010

14(sin 80) = 17(sin 17)

10. highschoolmom2010

$\frac{ 14 \sin 80 }{ 17 }=\frac{ 17 \sin Z }{ 17 }$

11. highschoolmom2010

whats where im lost

12. terenzreignz

^_^ You're actually doing great :) Now, 17 cancels out here: $\frac{ 14 \sin 80 }{ 17 }=\frac{ \cancel{17} \sin Z }{ \cancel{17} }$

13. terenzreignz

and we get... $\Large \sin Z = \frac{14\sin 80^o}{17}$

14. highschoolmom2010

but i plugged the remaining in calculator and got a crazy answer

15. terenzreignz

What was it? ^_^

16. highschoolmom2010

0.81101814953

17. highschoolmom2010

that cant be right

18. terenzreignz

Ahh... I see. Because what you got was the SINE of the angle Z :) You have to run it through $$\large \sin^{-1}$$ to get the angle Z itself ^_^ $\Large Z = \sin^{-1}\left(\frac{14\sin 80^o}{17}\right)$

19. highschoolmom2010

oh i forgot to do teh inverse

20. terenzreignz

There's your problem ^_^ I trust it no longer IS a problem? :D

21. highschoolmom2010

let me try that and see what i get '

22. terenzreignz

I'm sure it'll be more... believable... this time around ^_^

23. highschoolmom2010

54.1955269839

24. terenzreignz

More reasonable, don't you think? ^_^

25. terenzreignz

Correct, by the way :D

26. highschoolmom2010

thanks for the clarification :D

27. terenzreignz

No problem ^_^