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highschoolmom2010
 3 years ago
Law of sine question :DD
highschoolmom2010
 3 years ago
Law of sine question :DD

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AkashdeepDeb
 3 years ago
Best ResponseYou've already chosen the best response.0Why do you have a question if you know what the law of sines is?

highschoolmom2010
 3 years ago
Best ResponseYou've already chosen the best response.1im not sure if i am doing it right

cwrw238
 3 years ago
Best ResponseYou've already chosen the best response.0for a triangle ABC a/ sinA = b/sinB = c/sinC

highschoolmom2010
 3 years ago
Best ResponseYou've already chosen the best response.1dw:1377962024865:dw \[\frac{ \sin 80 }{ 17 }=\frac{ \sin Z }{ 14 }\]

highschoolmom2010
 3 years ago
Best ResponseYou've already chosen the best response.1like that ????

highschoolmom2010
 3 years ago
Best ResponseYou've already chosen the best response.114(sin 80) = 17(sin 17)

highschoolmom2010
 3 years ago
Best ResponseYou've already chosen the best response.1\[\frac{ 14 \sin 80 }{ 17 }=\frac{ 17 \sin Z }{ 17 }\]

highschoolmom2010
 3 years ago
Best ResponseYou've already chosen the best response.1whats where im lost

terenzreignz
 3 years ago
Best ResponseYou've already chosen the best response.1^_^ You're actually doing great :) Now, 17 cancels out here: \[\frac{ 14 \sin 80 }{ 17 }=\frac{ \cancel{17} \sin Z }{ \cancel{17} }\]

terenzreignz
 3 years ago
Best ResponseYou've already chosen the best response.1and we get... \[\Large \sin Z = \frac{14\sin 80^o}{17}\]

highschoolmom2010
 3 years ago
Best ResponseYou've already chosen the best response.1but i plugged the remaining in calculator and got a crazy answer

highschoolmom2010
 3 years ago
Best ResponseYou've already chosen the best response.10.81101814953

highschoolmom2010
 3 years ago
Best ResponseYou've already chosen the best response.1that cant be right

terenzreignz
 3 years ago
Best ResponseYou've already chosen the best response.1Ahh... I see. Because what you got was the SINE of the angle Z :) You have to run it through \(\large \sin^{1}\) to get the angle Z itself ^_^ \[\Large Z = \sin^{1}\left(\frac{14\sin 80^o}{17}\right)\]

highschoolmom2010
 3 years ago
Best ResponseYou've already chosen the best response.1oh i forgot to do teh inverse

terenzreignz
 3 years ago
Best ResponseYou've already chosen the best response.1There's your problem ^_^ I trust it no longer IS a problem? :D

highschoolmom2010
 3 years ago
Best ResponseYou've already chosen the best response.1let me try that and see what i get '

terenzreignz
 3 years ago
Best ResponseYou've already chosen the best response.1I'm sure it'll be more... believable... this time around ^_^

highschoolmom2010
 3 years ago
Best ResponseYou've already chosen the best response.154.1955269839

terenzreignz
 3 years ago
Best ResponseYou've already chosen the best response.1More reasonable, don't you think? ^_^

terenzreignz
 3 years ago
Best ResponseYou've already chosen the best response.1Correct, by the way :D

highschoolmom2010
 3 years ago
Best ResponseYou've already chosen the best response.1thanks for the clarification :D
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