anonymous
  • anonymous
How to measure the Co2 in alka-seltzer and then calculate the 3NaHCO3? How do you measure the mass in grams of NaHCO3, that is found in each tablet of Alka-Seltzer?
Chemistry
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
abb0t
  • abb0t
You can start by writing down the equation of your reaction with. Then, write the mass of the alka-seltzer, which can be found in the packet or by using a weight measuring machine.
abb0t
  • abb0t
Don't forget to balance the equation, that way, you can use dimensional analysis to calculate the theoretical yield of what you want to find.
anonymous
  • anonymous
C6H8O7+3NaHCO3----> 3H2O+3CO2+Na3C6H5O7

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anonymous
  • anonymous
Weight is 3.241 grams
abb0t
  • abb0t
Now, find the moles of sodium carbonate.s
abb0t
  • abb0t
Do you know how to do that?
anonymous
  • anonymous
no i dont
abb0t
  • abb0t
Well, start with the given grams of alkazelteser that you have. To start, compute the molar mass of it, which you can do by finding the sum of it's molecular formula. For example, molar mass has the units of \(\frac{mass}{mole}\), therefore, if you have H\(_2\), the molar mass of that is 1.008 \(\times\) 2 = 2.016 \(\frac{grams}{mol}\). Does that make sense? And very similar to how you did in algebra. you are going to use that relationship to cancel out the units. given grams of Alka-Seltz \(\times\) \(\frac{mol}{mass~of~alka-setlz}\) notice that the units of grams of alka-seltz cancel out? You will be left with moles. Then, take: mol of Alka-seltz \(\times\) \(\frac{\sf \color{red}{3}mol~NaHCO_3}{\sf \color{blue}{1} mol~alka-seltz}\) again, note that the units of mole cancel out. Now you have Mol's of NaHCO\(_3\)! Finally, multiply by the molar mass of NaHCO\(_3\) to get the molar mass! Now, based on your equation, it tells you that you have a 1:1 ratio of NaHCO\(_3\). So, mole of NaHCO\(_3\) = mol of CO\(_2\). Now, this is the amount of CO\(_2\) you would get if All the NaHCO\(_3\) fully reacted. It is called the theoretical yield of CO\(_2\). It is the amount of CO\(_2\) you are expecting to get, assuming that all the NaHCO\(_3\) reacts. Convert it to mass, SIMILARLY to how you did above.
abb0t
  • abb0t
Do you follow me? Or do you need more help. i am here.
anonymous
  • anonymous
yes sort of, so woukd the mol be 0.0073
anonymous
  • anonymous
Molar mass of NaHCO3 is 84g
anonymous
  • anonymous
I don't fully understand how the last part
abb0t
  • abb0t
I have to step out for a minute, but if you follow my steps, you should get the right answer. Sorry.
anonymous
  • anonymous
Alright thank you!

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