anonymous
  • anonymous
Solve the inequality. 4x<2x+1<=3x+2 I'm really just not understanding the algebra or possibly the rules to break it down and solve.
Precalculus
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
|dw:1377974882313:dw|
anonymous
  • anonymous
that what i got but hold on let me double check
anonymous
  • anonymous
But, how did you get it

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More answers

anonymous
  • anonymous
|dw:1377975017643:dw|
anonymous
  • anonymous
yea im not sure whats the answer, but the way i was taught to do this is since after the equal sign there is another equation, you put a line in the middle to break it down, and you solve them both separately until its small enough to combine
anonymous
  • anonymous
you put a line in the middle of less than and equal too
anonymous
  • anonymous
|dw:1377975097022:dw|
anonymous
  • anonymous
|dw:1377975163375:dw|
anonymous
  • anonymous
hold on im going to draw it
anonymous
  • anonymous
|dw:1377975223922:dw|
anonymous
  • anonymous
so i got zero for the answer
anonymous
  • anonymous
its sloppy but do you get that?
anonymous
  • anonymous
im kinda confused im not sure if i should of stopped at -1
anonymous
  • anonymous
but i hope that helps
anonymous
  • anonymous
Maybe I wasn't clear, the inequality is to be solved with intervals.
anonymous
  • anonymous
oh you tight then, idk -1,0
anonymous
  • anonymous
such inequalities should be first broken into the 2 parts , x interval should be computed and then the intersection of the intervals is the answer.
phi
  • phi
\[ 4x < 2x+1 ≤ 3x+2 \] is short for two different relations: \[ 4x < 2x+1 \\ 2x+1 ≤ 3x+2 \] Except for divide by a negative number (which will flip the relation operator), you solve these the same way you solve an equality. the first relation: 4x < 2x + 1 add -2x both sides 4x -2x < 2x - 2x + 1 simplify 2x < 1 divide both sides by 2 x < 1/2 the second relation 2x+1 ≤ 3x+2 add -2x to both sides 2x -2x + 1 ≤ 3x -2x +2 1 ≤ x + 2 add -2 to both sides 1 -2 ≤ x + 2 -2 -1 ≤ x you have x greater than or equal to -1: -1 ≤ x and x less than 1/2: x < 1/2 you can write that in "short hand" as -1 ≤ x < 1/2 on a numer line it would be graphed like this |dw:1377977048397:dw|
anonymous
  • anonymous
Thanks Phi, I understood exactly where to go once you showed how to separate them into two separate inequalities. I was stuck because I didn't process the fact that you can split them and have it be correct if the signs don't change direction by multiplication or division of -1.

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