anonymous
  • anonymous
......
Mathematics
  • Stacey Warren - Expert brainly.com
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katieb
  • katieb
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Littlebird
  • Littlebird
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anonymous
  • anonymous
1/5
anonymous
  • anonymous
isn't it y2-y1/x2-x1?

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anonymous
  • anonymous
now put it in y - y1 = m(x - x1) using 1/5 as slope(m) and either of your points (x1,y1)
anonymous
  • anonymous
that is the slope formula, but you already found the slope. Now use point slope formula because you have the slope and a point. Then we will find the equation of the line.
anonymous
  • anonymous
what?
anonymous
  • anonymous
like 4-3=(1/5)(3-(-2)?
anonymous
  • anonymous
use the point slope formula y - y1 = m(x - x1) using slope 1/5 and either of your points.... let me start it for you... y - y1 = m(x - x1).....slope(m) = 1/5 and points (3,4) y - 4 = 1/5(x - 3)
anonymous
  • anonymous
understand so far ?
anonymous
  • anonymous
ohhh
anonymous
  • anonymous
yeah now i do:)
Littlebird
  • Littlebird
In answer to your earlier question about my slope formula.... y2-y1/x2-x1 gives you the same answer as y1-y2/x1-x2
anonymous
  • anonymous
yes, you get the same answer y - 4 = 1/5(x - 3) -- distribute through the parenthesis y - 4 = 1/5x - 3/5 y = 1/5x - 3/5 + 4 y = 1/5x - 3/5 + 20/5 y = 1/5x + 17/5 you still with me ?
anonymous
  • anonymous
wait..where did u get the 20/5
anonymous
  • anonymous
I had to add -3/5 + 4, so I had to find the LCD, which was 5 and that made 4 = 20/5. Understand ?
anonymous
  • anonymous
ohh okay yeah
anonymous
  • anonymous
y = 1/5x + 17/5 we want it in standard form Ax + By = C. There is no fractions in this, so we have to get rid of our fractions by multiplying the equation by 5. when we do that, we get : 5y = x + 17 Are you understanding me ?
anonymous
  • anonymous
yesss
anonymous
  • anonymous
5y = x + 17 we will subtract x from both sides -x + 5y = 17 we do not want x to be negative, so we will multiply the equation by -1. x - 5y = 17 <-- standard form any questions ?
anonymous
  • anonymous
oops...x - 5y = -17
anonymous
  • anonymous
thank you soooooooo much!!!!!!! i understand it now :)
anonymous
  • anonymous
good to hear....happy I could help :)

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