anonymous
  • anonymous
If I have a45-45-90 triangle and they give me the length of the hypotenuse how can I find the length of the legs
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
helpppppppp
RadEn
  • RadEn
|dw:1377977181605:dw|
jdoe0001
  • jdoe0001
http://nanharbison.com/sats/math_images/45-45-90.gif use the 45-45-90 rule, notice the ratios

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anonymous
  • anonymous
Yes, but they give me 45 as the hypotnuse. what i dont undertsand is how to find the legs
anonymous
  • anonymous
42 i mean is the hypotnuse
anonymous
  • anonymous
1 Attachment
jdoe0001
  • jdoe0001
notice the picture drawn by RadEn , which one is the hypotenuse?
anonymous
  • anonymous
x sqrt of 2
anonymous
  • anonymous
is the hypotenuse
jdoe0001
  • jdoe0001
ahh, so we could say that, your value, that is your hypotenuse and the one in the 45-45-90 rule equate each other, or are equal, or we can say that \(\bf 42 = x\sqrt{2}\) solve for "x" :)
anonymous
  • anonymous
okay so for me to able to find the value of the legs i have to do 42 = x sqrt 2?
jdoe0001
  • jdoe0001
yes, the "legs" you have missing are, based on the 45-45-90 rule, "x" long
anonymous
  • anonymous
okay so if i was gonna solve 42= x sqrt of 2 how would i do that?
anonymous
  • anonymous
im sorry im just really confused im taking geometry online to be able to catch up for graduation and i am literally getting no help
jdoe0001
  • jdoe0001
well, think about "how would you solve" say 42 = x(a)
anonymous
  • anonymous
|dw:1377977872183:dw| is this how to solve it ?
jdoe0001
  • jdoe0001
hmm, well, not quite, you would want to "isolate" the variable "x" on the right-hand-side
jdoe0001
  • jdoe0001
\(\bf 42 = x(a) \implies \cfrac{\cancel{42}}{\cancel{42}}=\cfrac{x(a)}{42} \implies 1 = \cfrac{x(a)}{42}\) ?
anonymous
  • anonymous
how did you get the 1?
jdoe0001
  • jdoe0001
42/42 = 1
jdoe0001
  • jdoe0001
\(\bf \cfrac{anything}{anything} = 1\)
anonymous
  • anonymous
so then if i wanted to find \[42=\sqrt{2}\] I have to do the same steps? but what would i do after i get 1 = \[x \left( 2 \right) \over 42\]
jdoe0001
  • jdoe0001
well, you really didn't isolate "x", in fact it's more crowded than before, before it was just x(a) now is x(a)/42 but yes, pretty much, you'd simplify \(\bf 42 = x\sqrt{2}\) the same way
anonymous
  • anonymous
okay well thank you very much :) im gonna keep trying
jdoe0001
  • jdoe0001
yw
anonymous
  • anonymous
|dw:1377980329843:dw|

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