anonymous
  • anonymous
What is the limit for x--->infinity (r+sinr) / (2r+7-5sinr)
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
I guess you mean as r tend to infinity? Divide the top and bottom of the fraction both by r. Then use the fact: \[\lim_{r \rightarrow \infty} \frac{\sin r}{r} = 0\](since sin(x) remains bounded between -1 and 1, whereas r goes off to infinity.)
anonymous
  • anonymous
Yep, woops. Thank you
anonymous
  • anonymous
You're welcome :)

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rob1525
  • rob1525
Um both the top and bottom go to infinity...so...the limit shouldn't exist. let me verify with my calc.
rob1525
  • rob1525
Nope im getting 1/2. Humm.....
anonymous
  • anonymous
@robtobey Remember in maths \(\frac{\infty}{\infty}\) could be anything - it's basically meaningless. Just because the top of the fraction tends to infinity, and the bottom tends to infinity, does NOT mean the limit doesn't exist!
anonymous
  • anonymous
(Sorry, quoted wrong person!) @rob1525 See above.
rob1525
  • rob1525
oh, geees. if the sin are eliminated then ur left with x/2x which is a horizontal retricemtote of 1/2.
rob1525
  • rob1525
*asymptote

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