anonymous
  • anonymous
Am I doing this right? Suppose you roll an eight-sided die two times hoping to get two numbers whose sum is greater than 10. What is the sample space? How many favorable outcomes are there?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
so far my work is: 8 x 8 = 64 p(event) = number of favorable outcomes/total possible outcomes we have 21 possible outcomes that would equal ten: 3+8, 4+7, 4+8, 5+6, 5+7, 5+8, 6+5, 6+6, 6+7, 6+8, 7+4, 7+5, 7+6, 7+7, 7+8, 8+3, 8+4, 8+5, 8+6, 8+7, 8+8 so 21/64 x 100 = 32.8125 ------------ i'm not sure if i'm getting my answer properly.
cwrw238
  • cwrw238
looks good
anonymous
  • anonymous
oh ok

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anonymous
  • anonymous
i hope so
phi
  • phi
Yes, that is correct, but 1) you have a typo. You have "that would equal ten:" and mean "greater than ten" 2) The question did not ask for the probability, just the number of favorable outcomes. So you did extra work (unless they ask later on)
phi
  • phi
You could (tho it is tedious) draw an 8 x 8 matrix and label the columns and rows 1 through 8 then color in the favorable squares (where the row +column > 10)
anonymous
  • anonymous
thank you for pointing out the typo good eye

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