anonymous
  • anonymous
how many atoms are in .20 moles of lead
Chemistry
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SOLVED
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katieb
  • katieb
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abb0t
  • abb0t
0.2 moles \(\times\) \(\frac{atom}{6.022 \times 10^{23}mol}\) = atoms of Lead
anonymous
  • anonymous
@abb0t SorRy didn't gt it..
abb0t
  • abb0t
Don't get what?

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anonymous
  • anonymous
0.2 moles \(\times\) \(\frac{atom}{6.022 \times 10^{23}mol}\) = atoms of Lead
anonymous
  • anonymous
???
anonymous
  • anonymous
hmm....
theEric
  • theEric
\(1\ mol\ of\ atoms\approx 6.022\times 10^{23}\ atoms\\\implies1=\dfrac{6.022\times 10^{23}\ atoms}{1\ mol\ of\ atoms}\) @abbot , isn't that the conversion factor? So if you have \(0.20\ mol\ of\ lead\ atoms\), you multiply it by \(1\), the conversion factor. \(0.20\ mol\ of\ lead\ atoms\times\dfrac{6.022\times 10^{23}\ atoms}{1\ mol\ of\ atoms}\huge\longrightarrow\normalsize atoms\ of\ lead\) @Khiz , is this what you were thinking?
oOKawaiiOo
  • oOKawaiiOo
@theEric is right. abbot and khiz got them mixed around.
theEric
  • theEric
Alright! I think @KhiZ was confused by @abbot 's response, and posted abbot's equation as part of a question.
theEric
  • theEric
Thanks for checking, too, @oOKawaiiOo ! :)
oOKawaiiOo
  • oOKawaiiOo
np!
goformit100
  • goformit100
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anonymous
  • anonymous
Thanx @theEric :) Thatx exactly wht i ws thnking..
theEric
  • theEric
Cool! :) Glad we got that settled, then. :)
anonymous
  • anonymous
yupx :)

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