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Need quick help on half this problem? Bailey pulls a letter tile from a bag that contains one of each letter of the alphabet. Match each description of the tile with its probability.

Probability
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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1. a vowel in her name 2. a letter in her name or V 3. a letter in her name 4. a letter in her name or a consonant (Assume vowels are A, E, I, O, and U.) a. 12/13 b. 3/13 c. 7/26 d. 3/26 ---------------------------------------- I have matched "a vowel in her name" with 3/26 also matched "a letter in her name or v" with 7/26 however, I would believe that a letter in her name would be 6/26 and the last one would be 24/26
Hmmm..... maybe 6/26 is equivalent to one of the fractions given as options? Maybe 24/26 also? ;)
6/26 is equivalent to 12/13 and 24/26 is equivalent to 3/13

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Other answers:

i suppose that would actually work
noooo..... reduce 6/26. What's the common factor?
oh sorry i've been doing math all friggen day. im burnt out. it reduces to 3/13
remember, for two fractions to be "equivalent", you must be able to multiply the num'r and den'r of one of them by the SAME NUMBER, to produce the other fraction. E.g.: \[\Large \dfrac{ 21 }{ 28 }=\dfrac{ 7\cdot 3 }{ 7 \cdot4 }=\dfrac{ 3 }{ 4 }\]
yes
ok, right. You had them switched. :) And yes, that WILL work - it's the correct answer because fractions should be fully reducced.
oh yeah i forgot about reducing them. thank you very much for your time and help

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