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danijo1814
 one year ago
Need quick help on half this problem? Bailey pulls a letter tile from a bag that contains one of each letter of the alphabet. Match each description of the tile with its probability.
danijo1814
 one year ago
Need quick help on half this problem? Bailey pulls a letter tile from a bag that contains one of each letter of the alphabet. Match each description of the tile with its probability.

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danijo1814
 one year ago
Best ResponseYou've already chosen the best response.01. a vowel in her name 2. a letter in her name or V 3. a letter in her name 4. a letter in her name or a consonant (Assume vowels are A, E, I, O, and U.) a. 12/13 b. 3/13 c. 7/26 d. 3/26  I have matched "a vowel in her name" with 3/26 also matched "a letter in her name or v" with 7/26 however, I would believe that a letter in her name would be 6/26 and the last one would be 24/26

DebbieG
 one year ago
Best ResponseYou've already chosen the best response.1Hmmm..... maybe 6/26 is equivalent to one of the fractions given as options? Maybe 24/26 also? ;)

danijo1814
 one year ago
Best ResponseYou've already chosen the best response.06/26 is equivalent to 12/13 and 24/26 is equivalent to 3/13

danijo1814
 one year ago
Best ResponseYou've already chosen the best response.0i suppose that would actually work

DebbieG
 one year ago
Best ResponseYou've already chosen the best response.1noooo..... reduce 6/26. What's the common factor?

danijo1814
 one year ago
Best ResponseYou've already chosen the best response.0oh sorry i've been doing math all friggen day. im burnt out. it reduces to 3/13

DebbieG
 one year ago
Best ResponseYou've already chosen the best response.1remember, for two fractions to be "equivalent", you must be able to multiply the num'r and den'r of one of them by the SAME NUMBER, to produce the other fraction. E.g.: \[\Large \dfrac{ 21 }{ 28 }=\dfrac{ 7\cdot 3 }{ 7 \cdot4 }=\dfrac{ 3 }{ 4 }\]

DebbieG
 one year ago
Best ResponseYou've already chosen the best response.1ok, right. You had them switched. :) And yes, that WILL work  it's the correct answer because fractions should be fully reducced.

danijo1814
 one year ago
Best ResponseYou've already chosen the best response.0oh yeah i forgot about reducing them. thank you very much for your time and help
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