anonymous
  • anonymous
Using complete sentences, explain the two ways to simplify 320−−−√ and provide the simplified form.
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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AkashdeepDeb
  • AkashdeepDeb
Write it in the form of factors \[\sqrt{320} = \sqrt{2*2*2*2*2*2*5} = \sqrt{(2*2)*(2*2)*(2*2)*5} = 8*\sqrt{5}\] That should be your answer! :) To solve sums like these do it in the above method! :)
AkashdeepDeb
  • AkashdeepDeb
Or you can write \[\sqrt{320} = \sqrt{64*5} = 8*\sqrt{5}\] [Because 64 square root is 8 so it goes out side the root sign] Understood? :)
anonymous
  • anonymous
i have to explain in complete sentences

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AkashdeepDeb
  • AkashdeepDeb
Then try writing it in words!! B)
anonymous
  • anonymous
yes! :) What is the exact value of the expression \[11\sqrt{8}+6\sqrt{12}-5\sqrt{2}\]Show your work.
anonymous
  • anonymous
@AkashdeepDeb
AkashdeepDeb
  • AkashdeepDeb
Okay Now I am going to ask you to do this for me now okay? Try breaking down √8 and √12 in the form of [something*√2] ^_^ TRY IT!! :D
anonymous
  • anonymous
\[\sqrt{8}= like 3 \sqrt{12}=3.5\]
AkashdeepDeb
  • AkashdeepDeb
Not quite like I did before group everything in two's Like √8 = √2*2*2 = √4*2 [Now how much is square root of 4? 2!! :D] So √8 = 2√2 Now write √12 in this kind of form! :)
anonymous
  • anonymous
confused.
AkashdeepDeb
  • AkashdeepDeb
Do you know what cube-roots and square-roots are?
anonymous
  • anonymous
sqrt yes
AkashdeepDeb
  • AkashdeepDeb
What is the square root of 64?
anonymous
  • anonymous
8
AkashdeepDeb
  • AkashdeepDeb
And how did you get that?
anonymous
  • anonymous
8x8
AkashdeepDeb
  • AkashdeepDeb
Wow you are a model? : O
anonymous
  • anonymous
yes haha
AkashdeepDeb
  • AkashdeepDeb
Nice Okay Yes you are right about 8x8 but look carefully at this.. |dw:1377988243972:dw|
anonymous
  • anonymous
okay so 12 is the answer?
AkashdeepDeb
  • AkashdeepDeb
No No No......... :P But did you understand how I found out the square roots there?
AkashdeepDeb
  • AkashdeepDeb
Look as for your question 11√8 + 6√12 - 5√2 11*2√2 + 6*2√3 - 5√2 22√2 + 12√2 - 5√2 NOW WE CAN ADD/SUBTRACT BECAUSE WE HAVE A COMMON √2 29√2 That should be your answer! :) Understood? :)
anonymous
  • anonymous
oh okay! thank you :))
AkashdeepDeb
  • AkashdeepDeb
:)

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