anonymous
  • anonymous
Find an equation of the tangent line to the graph of f at the given point. f(x) = x^2 + 3, (1, 4)
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
katieb
  • katieb
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
tkhunny
  • tkhunny
Have you considered the 1st derivative, f'(x) evaluated at x = 1 to give the slope of this mysterious tangent line?
anonymous
  • anonymous
I don't know how to do this problem.
tkhunny
  • tkhunny
Have you heard of the 1st Derivative?

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
no
tkhunny
  • tkhunny
Is this a placement test?
anonymous
  • anonymous
no, homework. My teacher is foreign & hard to understand
tkhunny
  • tkhunny
What course is this? Is it Calculus I?
anonymous
  • anonymous
yes
anonymous
  • anonymous
if you can give me an equation, I can probably figure it out, just don't know what the (
tkhunny
  • tkhunny
Bear with me. Just trying to figure out where you are. Have you been introduced to an odd-looking ratio, like this \(\dfrac{f(x+h) - f(x)}{h}\)?
anonymous
  • anonymous
sorry I lost you. I know that equation, just don't know what the (1,4) is for?
tkhunny
  • tkhunny
The very first thing to do is to verify that (1,4) is actually ON the curve. Is it?
anonymous
  • anonymous
I don't think so
anonymous
  • anonymous
not totally sure how to read the graphs either
tkhunny
  • tkhunny
f(x) = x^2 + 3 f(1) = 1^2 + 3 = 1+3 = 4 (1,4) is on f(x) You ARE going to have to get better at some of these basic skills. This class is going to be a LONG HARD struggle if you don't remember anything from your prerequisites. Algebra I Algebra II Geometry Trigonometry Hopefully Analytic Geometry Hopefully "College Algebra" We're going to need all the algebra and geometry skills we can get to survive just today. What do you think? Are you up to it?
anonymous
  • anonymous
I am. This is my last math class, so I do need to pass it. Thank you!
tkhunny
  • tkhunny
Okay, then... In the Differential Calculus, we have this amazing thing known as the 1st Derivative. It can be loosely defined as the slope of the tangent line at any given point on a curve (where it works, anyway). Our task is to define a little more carefully exactly what that means. You may be familiar with a line tangent to a circle. It is a line that just touches the circle. There is only one point of intersection. If you hit the circle twice, it is a secant line. How are we doing? Up to speed on these concepts?

Looking for something else?

Not the answer you are looking for? Search for more explanations.