anonymous
  • anonymous
This should be pretty easy. However, I thought both questions meant the same thing. Apparently not. Problem: A particle's position is given by x = 8.00 - 12.00t + 3t^2, in which x is in meters and t is in seconds. (a) What is its velocity at t = 1 s? (b) What is its speed just then?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
take the derivative and replace \(t\) by \(1\)
anonymous
  • anonymous
And I get -6
anonymous
  • anonymous
ok

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anonymous
  • anonymous
then the velocity is \(-6\) and the speed is \(|-6|=6\)
anonymous
  • anonymous
why does the speed have an absolute value and the velocity doesn't. That's what I'm not getting
anonymous
  • anonymous
speed is positive
anonymous
  • anonymous
for example, if you get in your car, put it in reverse, and drive at 10 mph in reverse, your speed is 10 mph but your velocity is -10 since you are going backwards
anonymous
  • anonymous
or as a less silly example, if a rock is falling at a rate of 6 meters per second, then the speed is 6 meters per second, but the velocity is -6 because it is going down, not up
anonymous
  • anonymous
ah ok
anonymous
  • anonymous
Thank you!!!
anonymous
  • anonymous
yw

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