This should be pretty easy. However, I thought both questions meant the same thing. Apparently not.
Problem: A particle's position is given by x = 8.00 - 12.00t + 3t^2, in which x is in meters and t is in seconds. (a) What is its velocity at t = 1 s? (b) What is its speed just then?

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take the derivative and replace \(t\) by \(1\)

And I get -6

ok

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