I'm not sure how to start this one. Acceleration= 9.8 m/s^2.
Water drips from the nozzle of a shower onto the floor 182 cm below. The drops fall at regular (equal) intervals of time, the first drop striking the floor at the instant the fourth drop begins to fall. When the first drop strikes the floor, how far (in cm) below the nozzle are the (a) second and (b) third drops?
Stacey Warren - Expert brainly.com
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i am a bit confused myself, but i think we can do this:
\[a=-9.8\] ( it should be negative, because gravity sucks)
\[v(t)=-9.8t\] by integrating
the constant is zero, because the initial velocity (i assume) is 0
\[p(t)=-4.9t^2+182\] and now you can see how long it take for the drop to hit the floor by setting
\[-4.9t^2=182=0\] and solving for \(t\)
shouldn't a be positive because it's heading towards the center of the earth?
and that would make the value of t a real number rather than an imaginary number