anonymous
  • anonymous
I'm not sure how to start this one. Acceleration= 9.8 m/s^2. Water drips from the nozzle of a shower onto the floor 182 cm below. The drops fall at regular (equal) intervals of time, the first drop striking the floor at the instant the fourth drop begins to fall. When the first drop strikes the floor, how far (in cm) below the nozzle are the (a) second and (b) third drops?
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
katieb
  • katieb
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
i am a bit confused myself, but i think we can do this: \[a=-9.8\] ( it should be negative, because gravity sucks) then \[v(t)=-9.8t\] by integrating the constant is zero, because the initial velocity (i assume) is 0 to \[p(t)=-4.9t^2+182\] and now you can see how long it take for the drop to hit the floor by setting \[-4.9t^2=182=0\] and solving for \(t\) sound reasonable?
anonymous
  • anonymous
shouldn't a be positive because it's heading towards the center of the earth?
anonymous
  • anonymous
and that would make the value of t a real number rather than an imaginary number

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
\[-4.9t^2+182=0\] \[182=4.9t^2\] etc it is negative because it is going down
anonymous
  • anonymous
and the solutions are not imaginary
anonymous
  • anonymous
oh oops
anonymous
  • anonymous
The thing is, at my school we are being taught that if for instance, the ball goes down it has a gravity of 9.8 m/s^2
anonymous
  • anonymous
or maybe i just misheard
anonymous
  • anonymous
thanks anyway
aaronq
  • aaronq
|dw:1378012224154:dw| I think you could just do this.

Looking for something else?

Not the answer you are looking for? Search for more explanations.