6 (3-x) = -4 (2x-1) Find x Value The X Value is 7 or -7 just can't figure out how to get the answer

- EvonHowell

6 (3-x) = -4 (2x-1) Find x Value The X Value is 7 or -7 just can't figure out how to get the answer

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- jamiebookeater

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- EvonHowell

And I got alot more of this crap and my teacher didn't tell me how to do them

- anonymous

6(3- x) = -4(2x - 1)
the first thing you want to do is distribute the 6 and the -4 through the parenthesis. Can you do that ?

- EvonHowell

I know what distribute means but don't know how to do it exactly

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## More answers

- anonymous

6(3 - x) = 6 * 3 - 6 * x
and -4(2x - 1) = -4 * 2x - (-4) * 1
understand ?

- anonymous

let me restate that second one....-4 * 2x + -4 * -1

- EvonHowell

soo 12x = 13x?

- anonymous

6(3 - x) = -4(2x - 1)
18 - 6x = -8x + 4
can you take it from here because I have to go...sorry

- anonymous

18 - 6x = -8x + 4
subtract 18 from both sides
-6x = -8x + 4 - 18
-6x = -8x - 14
now add 8x to both sides
-6x + 8x = -14
2x = -14
x = -7
sorry I couldn't explain better, I have to go now

- EvonHowell

-6x - 90 = 9x

- EvonHowell

Tho I am so lost with all this stuff

- thomaster

subtract 9x on both sides and add 90 on both sides
You'd get -15x=90
now divide by -15

- thomaster

The point is that you bring the variables (x in this case) to the left side of the equation, and the numbers to the right side.

- EvonHowell

-6 is the answer?

- thomaster

\(\large\dfrac{~~90}{-15}=-6\) so yea

- EvonHowell

so whats about 3x - 4 = 10-4x How would i do this one

- thomaster

bring numbers to the right, x to the left.
To bring x to the left, you would have to add 4x on both side.
That way, you can cancel the -4x on the right.
\(\large3x - 4 = 10-4x\)
\(\large3x~\underline{+4x} - 4 = 10-4x~\underline{+4x}\)
\(\large7x - 4 = 10\)

- thomaster

Now you only have to bring -4 to the right
Just add 4 on both sides and you'll cancel the -4 on the left.
So it'll become: 7x=14
now you divide 14 by 7 to solve for x

- EvonHowell

x=2

- thomaster

exactly :)

- EvonHowell

can we do 2 more?

- thomaster

sure

- EvonHowell

-7 - (-4x) = -4x+9

- EvonHowell

oops 2 more after this 1 my bad

- thomaster

Alright first of all: -(-4x) is the same as +4x

- thomaster

So the equation would be -7 +4x = -4x+9

- thomaster

now we want that -7 on the other side of the equation, so we add 7 on both sides
4x=-4x+16

- thomaster

last thing is to add 4x on both sides to get that -4x to the left
8x=16
Do you know what to do now?

- EvonHowell

Divide both sides by 8?

- thomaster

Yep :)

- EvonHowell

x=2

- thomaster

correct

- EvonHowell

|dw:1378003846241:dw|

- thomaster

We first want to get rid of the fractions. To do that, multiply everything with the denominator. They're both 10 here so we can multiply everything with 10

- EvonHowell

30x= 7-70x?

- thomaster

\(\Large\sf\dfrac{3}{10}*10=\ ?\)

- EvonHowell

3?

- thomaster

Yep, also don't forget to multiply 7 by 10

- EvonHowell

3x=70-7x?

- thomaster

yes :)
Do you know what to do next?

- EvonHowell

-7x from both sides?

- thomaster

there already is a -7x on the right side.
you won't cancel it out with you subtract 7x... it would be 3x = 70 -14x then

- EvonHowell

ok then idk.

- thomaster

You don't subtract the 7x, you have to add it to both sides :)

- EvonHowell

ooh ok

- thomaster

because -7x + 7x = 0
It would dissapear on the right side of the equation

- EvonHowell

9x=70

- EvonHowell

then divide by 9

- thomaster

3+7 = 9?

- EvonHowell

oops 10

- EvonHowell

so x=10

- thomaster

No 10x = 70

- EvonHowell

yes 10x=7- then divide by 10 the tens on the left would cancel leaveing 70/10 which would diide into 10 soooo x=10

- EvonHowell

70* for the first part sorry

- thomaster

70/10 = ?

- EvonHowell

oh dear god x=7 i'm stupid

- thomaster

haha just small mistakes :) happens to the best

- EvonHowell

LAST ONE!! 1/6 (6-x) = 27 + 2x

- thomaster

\(\large\dfrac{1}6(6-x)=27+2x\)
Any idea how to get rid of that fraction?

- thomaster

Oh wait

- thomaster

First distribute it :)

- EvonHowell

How do I distribute a fraction again?

- thomaster

so \((\dfrac{1}6 * 6)-(\dfrac{1}6*x)\)

- thomaster

|dw:1378005185572:dw|

- EvonHowell

uh..

- thomaster

\(\large\sf\dfrac{1}6*6=\ ?\)

- EvonHowell

1

- EvonHowell

i think i have no clue but think it is 1

- thomaster

Yes,
And \(\large\sf\dfrac{1}6*x=just\ \dfrac{1}6x\)

- thomaster

So now that you have distributed the 1/6, The equation would be:
\(\Large\sf1-\dfrac{1}6x=27+2x\)

- thomaster

Now we can get rid of the fraction by multiplying everything by 6

- EvonHowell

soo 1-6x=27+2x ooorrr 6x=27+2x

- thomaster

Multiply everything by 6, what do you get?

- EvonHowell

6x=27+2x? I'm lost now

- thomaster

Just multiply every individual part by 6
So 1*6 = 6
1/6x * 6 = 1x
27*6=162
2*6=12
So now you'd have: \(\Large\sf6-x=162+12x\)

- thomaster

Do you know what to do now?

- EvonHowell

subtract 12 from both sides??

- thomaster

exactly

- thomaster

actually subtract 12x

- EvonHowell

so than that would go to -6=162?

- EvonHowell

or -6x?

- thomaster

-x-12x=?

- EvonHowell

-12x? o.O

- thomaster

|dw:1378006268757:dw|

- thomaster

it's the same as -1-12, it would be -13

- EvonHowell

so -13=162??

- thomaster

Don't forget about the 6 in front of -13\(\large\sf x\)

- thomaster

6-13x=162

- EvonHowell

ok i would subtract 13x from 6?

- thomaster

you can't subtract a variable from a number...
You'd have to subtract 6 from both sides

- EvonHowell

so 13x=156

- thomaster

-13x=156

- EvonHowell

yeahh my bad so dived by -13 the -13 on the left would cancel out so x=-12

- thomaster

That's correct :) great job

- EvonHowell

Thank You!!!!!! Ok now i'm done with my math thanks soo much!!

- thomaster

No problem \(\LARGE\ddot\smile\)

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